Pls help extra points and mark brainlist

Mathematics

2 answers:

sashaice [31]2 years ago

7 0

B, C, and D.

All you have to do is substitute 8 in these equations for the easy answer.
A) 8 + 11 = 15 (False, it equals 19)
B) 1 = 8 / 8 (True)
C) 15 + 8 = 23 (True)
D) 42 = 7(8) (False, 7 times 8 equals 56)
E) 8 - 5 = 3 (True)

Inessa [10]2 years ago

6 0

Answer:

B. C. and E.

Step-by-step explanation:

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3 years ago

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A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true

kvv77 [185]

Answer:

99.74% probability that the sample proportion will be less than 0.1

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .