The first one is 9/16 you have to make 54 and 96 a fraction such as 54/96 then simplify
the second one is 1/5 you have to make 4 and 20 a fraction like this 4/20 then simplify
hope this helps!!
Answer:
I believe its B, sorry if im wrong
Step-by-step explanation:
Answer:
b. 
f. 17 hours
Step-by-step explanation:
Charges for coming to my house = $68 (this will be the constant of the equation)
Amount charged per hour labor = $17
hours = h
Total amount paid to Mike = 357
The equation that represents this situation can be expressed as:

Solve for h
(subtraction property of equality)

(division property of equality)

Mike was in my house for 17 hours.
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
Step-by-step explanation:
total working duration = 2 weeks
Working duration in hours = 38× 2= 76 hours
a) per year
24*3115.35 = $74768
b) 3115.35/2
$1557.675
c)
3115.35/76
$40.99