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const2013 [10]
3 years ago
9

Jenny is building a rectangular garden around a tree in her yard. The southwest corner of the garden will be 2 feet south and 3

feet west of the tree. The northwest corner of the garden is 1 foot north and 4 feet east of the tree. What will be the perimeter of Jenny's garden ?
A. 10 ft
B. 20 ft
C. 21 ft
D. 25 ft
Mathematics
2 answers:
Vanyuwa [196]3 years ago
5 0
There are numerous important information's already given in the question. Based on those information's the answer can be easily determined. From the information's given, we get the coordinates as (-3, -2) and (4, 1). From these co ordinates, we can say that
Height of the rectangle is 3 feet
Length of the rectangle is 7 feet
Then
Perimeter of the rectangle = 2( length + Height)
                                          = 2(7 + 3)
                                          = 2 * 10    
                                          = 20 feet
From the above deduction, we can conclude that the correct option is option "B".
julia-pushkina [17]3 years ago
4 0

1. B

2. B

3. C

4. B

5. C

6. D

7. B

8. D

9. A

10. C


100% Correct

Hope this helps! :)


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Answer:

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

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