Question

A certain function h(x) contains the point (8,-2). Find the value of h^-1(-2) . Explain your answer.

Answer 1

Given:

A certain function h(x) contains the point (8,-2).

To find:

The value of $h^{-1}(-2)$.

Solution:

If a function is defined as

$f(x)=\{(a,b):a\in R,b\in R\}$

Then, its inverse is defined as

$f^{-1}(x)=\{(b,a):a\in R,b\in R\}$

It is given that, a certain function h(x) contains the point (8,-2). It means, its inverse $h^{-1}(x)$ contains the point (-2,8). So, the value of inverse function is 8 at x=-2, i.e.,

$h^{-1}(-2)=8$

Therefore, the value of $h^{-1}(-2)$ is 8.