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Lady_Fox [76]
2 years ago
8

Solve the equation and enter the value of x below. x(8 + 9) = 34​

Mathematics
1 answer:
vodomira [7]2 years ago
5 0

\huge\boxed{\mathfrak{Answer}}

x(8 + 9) =  34 \\ 8x + 9x = 34 \\ 17x = 34 \\ x =  \frac{34}{17}  \\ x = 2

=> The answer is <u>2</u><u>.</u>

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the amount of a $3,000.00 annuity due at 12 percent compounded semiannually for 3 years. A. $334,321.00 B. $43,068.93 C. $22,180.50 D. $41,814.50

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2 years ago
When factoring x2 – 3xy + 2y2 by grouping the first step can be:
blagie [28]

Answer:

x^2 – 3xy + 2y^2

Step-by-step explanation:

Factor the following:

x^2 - 3 x y + 2 y^2

Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.

The factors of 2 that sum to -3 are -1 and -2. So, x^2 - 3 x y + 2 y^2 = (x - 1 y) (x - 2 y):

Answer:  (x - y) (x - 2 y)

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3 years ago
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Around 50 free throws she will miss
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2 years ago
Divide £250 in the ratio 3:6:1
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Answer:

Step-by-step explanation:

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Stay safe; stay healthy!

8 0
2 years ago
HI can you help me with this problem?The quantity demanded x for a certain brand of MP3 players is 300 units when the unit price
Vlad [161]

The demand equation is P = -0.05x + 105

STEP - BY - STEP EXPLANATION

What to find?

<em>The demand equation.</em>

The following information is used to solve the problem.

If (x₁ , y₁) and (x₂, y₂) are any dinstinct points on a line a non-vertical line L, then the equation of the line that has a slope(m) and passes through the point (x₁ , y₁) is given by the formula below:

y-y_1=_{}\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Assume p, be the unit price and x be the demand when the price is $p.

From the question given, when the unit price x = 300 units, the demand p = $90 and when the unit price x = 1300 units, the demand p = $40

This means the demand curve passes through the points (300, 90) and (1300, 40).

Assume the demand equation is linear, then the line of the equation passes through the points (300, 90) and (1300, 40).

Now;

y=p x₁ =300 y₁ = 90 x₂ = 1300 y₂=40

Substitute the values into the function and simplify.

p-90=\frac{40-90}{1300-300}(x-300)

Simplify the above.

p-90=\frac{-50}{1000}(x-300)p-90=-0.05(x-300)

Open the parenthesis.

P- 90 = -0.05x + 15

Add 90 to both-side of the equation.

P = -0.05x + 15 + 90

P = -0.05x + 105

Hence, the demand function is P = -0.05x + 105

6 0
11 months ago
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