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netineya [11]
2 years ago
10

The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.

Mathematics
1 answer:
Dovator [93]2 years ago
3 0

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

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Answer:

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Step-by-step explanation:

Let us revise some cases of reflection

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  • If the point (x, y) reflected across the y-axis , then its image is (-x, y)
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From the given figure

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→ Switch the two coordinates

∴ The coordinates of its image G' are (-5, 4)

∴ The coordinates of the image of vertex G are (-5, 4)

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