B.C. counts down to 0, and that's when A.D. starts counting up. That means you can add 582 and 1643, to get their difference. Pythagoras and Newton were born 2,225 years apart.
Answer:
16.5 ft by 25.5 ft
Step-by-step explanation:
Let w represent the width of the garden in feet. Then w+9 is the garden's length, and w(w+9) represents its area.
The surrounding walkway adds 8 feet to each dimension, so the total area of the garden with the walkway is ...
(w+8)(w+9+8) = w^2 +25w +136
If we subtract the area of the garden itself, then the remaining area is that of the walkway:
(w^2 +25w +136) - (w(w+9)) = 400
16w + 136 = 400 . . .simplify
16w = 264 . . . . . . . . subtract 136
264/16 = w = 16.5 . . . . . width of the garden in feet
w+9 = 25.5 . . . . . . . . . . .length of the garden in feet
Assuming that b>0 and c>0:
log(a)=3×log(b)-2×log(c)=
log(b³)-log(c²)=
log(b³/c²)
Hence a=b³/c²
To reduce the radical, you have to factorize 108.
108 is a multiple of 3, so to factorize it, you can divide it by 3
You can rewrite the square root as:
![\sqrt[]{3\cdot36}=\sqrt[]{3}\cdot\sqrt[]{36}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5Ccdot36%7D%3D%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D)
The square root of 36 is equal to 6 so you can write the expression as:
![\sqrt[]{3}\cdot\sqrt[]{36}=6\sqrt[]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D%3D6%5Csqrt%5B%5D%7B3%7D)
