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9966 [12]
3 years ago
12

Drag and drop the correct choice into each box.

Mathematics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

18 quarts.

1.875 quarts.

100÷3

Step-by-step explanation:

Step 1: How much sparkling water would you need to mix with 9 quarts of grape juice?

sparkling

water              grape juice

      1.5       3/4

      X       9

we know that  9÷0.75 = 12 and 9×12 = 108

Hence we would need 18 quarts of sparkling water.

Step 2 : how much grape juice would you need to mix with 3.75 quarts of sparkling water?

sparkling       grape juice

water

1.5              3/4

15/4      1.875

1.875 can also be expressed as 1(7÷8) this ÷2 or (1÷2) we get the answer.

you would need 1(7÷8) quarts of juice.

Step 3 :How much of each ingredient would you need to make 100 quarts of punch

=200÷3 for sparkling water

=100÷3 for grape juice.

100×3 =  300.

Step-by-step explanation:

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John is saving ⅔ of his allowance each week for a wireless headphones that he wants to buy. After 6 weeks he has$87 saved for th
cestrela7 [59]

Answer:

21.75

Step-by-step explanation:

if you take 87 divided by 2/3, you get 130.5, which is the total amount of money he makes in 6 weeks. but if you take 130.5 divided by 6, you get 21.75 which is how much he makes weekly.

6 0
3 years ago
catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts. A banquet committee is to select 7 ​appetizers, 8 main​
guapka [62]

Answer:  The required number of ways is 46200.

Step-by-step explanation:  Given that a catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts.

A banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in ^nC_r ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,

the number of ways in which 8 main courses can be chosen from 11 main courses is

n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165

and the number of ways in which 4 desserts can be chosen from 7 desserts is

n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.

Therefore, the number of ways in which the banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts is given by

n=n_1\times n_2\times n_3=8\times165\times35=46200.

Thus, the required number of ways is 46200.

7 0
4 years ago
Speedy crawled 5/9 yards. Slimy crawled 4 times as far as speedy. How far did slimy crawl?​
ELEN [110]

Answer:

2 2/9 yards or 20/9 yards

Step-by-step explanation:

Slimy went 4 times as much as Speedy did so that means 5/9 x 4 yards which is the same thing as 5 x 4/9 so 5 x 4/9 equals 20/9 or 2 2/9 so Slimy crawled 2 2/9 yards.

5 0
3 years ago
What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers
Dafna1 [17]

Answer:

a) \pm 8\frac{x^{5}}{5}+C

b) \pm 4 sin(2x) + C

Step-by-step explanation:

Given integrals are:

a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx ---(1)

b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx---- (2)

Standard form

                L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx

<h3>Part A</h3>

compare (1) with standard form

[f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C

<h3>Part B</h3>

Compare (2) with standard form

[f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C

5 0
3 years ago
Twice the sum of two numbers is 36 If one of the numbers is 10 find the other number​
Dahasolnce [82]

Answer:

8

Step-by-step explanation:

10 + 8 = 18

18 x 2 = 36

3 0
3 years ago
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