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3 years ago

How many times larger is 6x10^3 than 2x10^2

Mathematics

1 answer:

Alecsey [184]3 years ago

7 0

30 times greater I hope it helps unlike that other answer...

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Subtract. Write your answer in simplest form. 9 1/2- 1 6/7

yaroslaw [1]

The answer is 9 1/2 - 1 6/7 = 4 1/8 hoped this helped

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2 years ago

{(-5, 4), (-4,-1), (-2, 1), (0, 4), (1,3)} i need to find the domain and range

aniked [119]

Domain : (-5, -4, -2, 0, 1)
range : (4,-1, 1,4,3)

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2 years ago

If a /b = p /q, then (a + b )/b = _______. (p + b )/q (p + p)/q (p + q)/q (p + a)/q

maxonik [38]

Hope this helps you!

5 0

3 years ago

Read 2 more answers

A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti

prohojiy [21]

ANSWER

Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

To proof

let us assume that the fluid should be drained and replaced with pure antifreeze be x .

As given

A radiator contains 10 quarts of fluid, 30% of which is antifreeze.

Now write 30% in the decimal form

$= \frac{30}{100}$

Now write 60% in the decimal form

$= \frac{60}{100}$

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )

The quantity of antifreeze is

$= \frac{30\times (10 - x)}{100}$

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

than the equation becomes

$= x + \frac{30\times ( 10 - x )}{100} = \frac{60\times10}{100}$

solyving

100x +300 - 30x = 600

70x = 300

$x = \frac{300}{70}$

x = 4.28 quarts (approx)

Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .

Therefore the option (c.) is correct .

3 0

3 years ago

Read 2 more answers

Please help!!!!

Solnce55 [7]

Answer:

c) ( $(6-\sqrt{12} )(6+\sqrt{12} ) = 24$

d) ( $(3+\sqrt{8} )(3-\sqrt{8} ) = 1$

Step-by-step explanation:

Step(i):-

Given that the binomial expression

( $(6-\sqrt{12} )(6+\sqrt{12} )$

Multiply

( 36 + 6√12 -6√12 -(√12)²)

= ( 36 -12)

= 24

c) ( $(6-\sqrt{12} )(6+\sqrt{12} ) = 24$

Step(ii):-

Given that the binomial expression

( $(3+\sqrt{8} )(3-\sqrt{8} )$

Multiply

= 9 - 3√8 + 3√8 -(√8)²

= 9 - 8

= 1

d) ( $(3+\sqrt{8} )(3-\sqrt{8} ) = 1$

8 0

2 years ago