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3 years ago

Help? Please...............

Mathematics

1 answer:

siniylev [52]3 years ago

8 0

Answer:

Step-by-step explanation:

→ Find the scale factor increase

6 ÷ 4 = 1.5

→ Multiply the scale factor by the corresponding length

2 × 1.5 = 3

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3/4 picked apples. If 120 students picked apples, how many picked bananas

Oxana [17]

Answer:

40 students picked bananas

Step-by-step explanation:

3/4 picked apples

1 - 3/4 = 1/4 picked bananas

3/4x = 120

Multiply both sides of the equation by 4/3

4/3 * (3/4x) = 120/1 * (4/3)

x = 480/3

x = 160

Total of 160 students

/ \

120 = apples 160 - 120 = 40 = bananas

40 students picked bananas

Hope this helps :)

6 0

3 years ago

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Which expression is equivalent to (2x^2)(3x^3)(4x)^2?

otez555 [7]

(2x^2)(3x^3)(4x)^2

=6x^5(16x^2)

=96X^7

8 0

3 years ago

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Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors $\vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a).$ These vectors are collinear, then

$\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.$

Answer 5: $-\dfrac{a}{b}=-\dfrac{d}{c}.$

5 0

3 years ago

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Circle 1 has a center (−4, 5) and a radius of 6 cm. Circle 2 has (2, −3) and a radius of 9 cm. What transformations can be appli

beks73 [17]

Answer:

The circles are similar because the transformation rule (+ 5 , - 6) can be applied to Circle 1 and then dilate it using a scale factor of 3/4.

Step-by-step explanation:

All the circles are similar.

That is because you can transform one circle onto another by two similarity operations: translation and dilation (scale factor).

For these two circles you have to translate the center of circle 1 to the center of circle 2, which will make that the two circles are concentric (have the same center).

The two centers are (-6,2) and (-1,- 4). To move the center (-6, 2) to (-1,4) you have to shift it 5 units to the right and 6 units down:

- 6 + 5 = - 1

2 - 6 = - 4.

After this translation, you dilate the circle with smaller radius using a scale factor equal to the ratio of the bigger radius to the smaller radius: 8/6 = 4/3.

Enter the scale factor as a fraction in simplest form. 3/4

The circles are similar because the transformation rule (+5 , - 6) can be applied to Circle 1 and then dilate it using a scale factor of 3/4.

7 0

3 years ago

What’s 4.8989 rounded to the nearest hundredth?

raketka [301]

Answer:

4.90

Step-by-step explanation:

5 0

3 years ago

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