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yuradex [85]
3 years ago
12

∠WXY and ∠ZXY are adjacent angles. What equation must always be TRUE? m∠WXY=m∠ZXY

Mathematics
1 answer:
Hitman42 [59]3 years ago
3 0

Answer:

m∠WXY+m∠ZXY=m∠WXZ

Step-by-step explanation:

You don't know the angles to be congruent (equal measures), complementary (measures add to 90 deg), or supplementary (measures add to 180 deg); all you know is that they are adjacent, so the sum of the measures of the two smaller angles equals the measure of the larger outer angle.

Answer: m∠WXY+m∠ZXY=m∠WXZ

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The expression 50 can be simplified to
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Answer:

25

Step-by-step explanation:

The first step in simplifying the expression of the square root of 50 involves finding factors of 50. This just means we are trying to find two whole numbers that, when multiplied, equal 50. Since 50 is an even number, 2 is going to be a factor, and so we can rewrite 50 as 2 times 25.

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2 years ago
A and B are two events. Which statement about the conditional probability is true?
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The answer 
by using fundamental definition
<span>The conditional probability of event B given event A is P(B|A)=P(A and B)/P(A) when two events are not independent.
so the only true answer is A, because </span>P(B|A)=P(A) if A and B are independents<span>
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4 0
3 years ago
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(-5,-3) (5,5)<br> slope<br> What is the slope ?
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Answer:

The slope is 10/8

Step-by-step explanation:

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Given points A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1), which of the following proves that
damaskus [11]

Similar triangles may or may not have equal side lengths

Triangles ABC and DEF are similar by SSS theorem

<h3>How to determine the similarity statement</h3>

The coordinates of the two triangles are:

A (0,0), B (4,0), C (0,2), D (0,0), E (2,0), and F (0,1)

Calculate the lengths of both triangles using the following distance formula

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

For triangle ABC, we have:

AB = \sqrt{(0 -4)^2 + (0 -0)^2} = 4

BC = \sqrt{(4 -0)^2 + (0 -2)^2} = 2\sqrt 5

CA = \sqrt{(0 -0)^2 + (0 -2)^2} = 2

For triangle DEF, we have:

DE = \sqrt{(0 -2)^2 + (0 -0)^2} = 2

EF = \sqrt{(2 -0)^2 + (0 -1)^2} = \sqrt 5

FD = \sqrt{(0 -0)^2 + (1 -0)^2} = 1

Divide corresponding sides of the triangles to calculate the scale factor k

k = \frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}

This gives

k = \frac{4}{2} = \frac{2\sqrt 5}{\sqrt 5} = \frac{2}{1}

Evaluate the quotients

k = 2 = 2 = 2

Since the quotients are equal, then the triangles are similar

Hence, triangles ABC and DEF are similar by SSS theorem

Read more about similar triangles at:

brainly.com/question/14285697

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Use the function to fill in the blanks in the table.
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Answer:

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Step-by-step explanation:

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