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Monica [59]
3 years ago
6

Can someone help me with this math homework please!

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

250 + 200h = 300 + 180h

200h – 180h = 300 – 250

20h = 50

H = 2.5 credit hours

Step-by-step explanation: Hope this helps and good luck :))

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The answer is D and i showed the work

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3 years ago
What is the square root of 41
Molodets [167]
6.043124 is the answer
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3 years ago
Read 2 more answers
*EASY 7TH GRADE MATH*
lora16 [44]

Answer:

2880

Step-by-step explanation:

The base is made up of two triangles and a square, if that makes sense. Finding the area of a triangle is (base x height)/2.  

The base of the tiny triangle is 4 because there is 8 inches extra to the 10 inch square. <u>10 x 4 = 40.</u>

Now we have a 10 by 10 square: <u>10 x 10 = 100. </u>

So, the area of the trapezoid is 140. There are two trapezoids in this prism, so both bases are 280.

The surface area of the sides are solved by <u>12 x 50 = 600. </u>Together, the sides equal 1200.

The top is solved by <u>10 x 50 = 500.</u>

The bottom is solved by <u>18 x 50 = 900.</u>

Add them all together: 280 + 1200 + 500 + 900 = 2,880

4 0
3 years ago
an apple pie was cut into 4 equal slices one slice was quickly eaten what fraction of the pie was left
pantera1 [17]
It is 3/4 of the pie is left because one slice is 1/4 of the pie and taking 1/4 from 4/4 is 3/4
8 0
3 years ago
Express sin A, cos A, and tan A as ratios ​
vlabodo [156]
<h3>Answer: Choice B</h3><h3>sqrt(3)/2,    1/2,   sqrt(3)</h3>

================================================

Explanation:

Sine of an angle is the ratio of the opposite side over the hypotenuse. For reference angle A, the opposite side is BC = 6sqrt(3). The hypotenuse is the longest side AB = 12

Sin(angle) = opposite/hypotenuse

sin(A) = BC/AB

sin(A) = 6sqrt(3)/12

sin(A) = sqrt(3)/2

---------------

Cosine is the ratio of the adjacent and hypotenuse

cos(angle) = adjacent/hypotenuse

cos(A) = AC/AB

cos(A) = 6/12

cos(A) = 1/2

---------------

Tangent is the ratio of the opposite and adjacent

tan(angle) = opposite/adjacent

tan(A) = BC/AC

tan(A) = 6sqrt(3)/6

tan(A) = sqrt(3)

5 0
3 years ago
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