Answer:
(Choice A)
Juanita gets a strike next game.'
Step-by-step explanation:
Your question is obviously incomplete.
Complete question is:
Juanita and Nina are bowling together. The probability of Juanita getting a strike next game is 24%. The probability of Nina getting a strike next game is 0.17. Which of these events is more likely?
(Choice A)
Juanita gets a strike next game.'
(Choice B)
Nina gets a strike next game.
(Choice C)
Neither. Both events are equally likely.
Answer:
Probability of Juanita : P(J)= 24% => 0.24
probability of Nina getting a strike next game: P(N) = 0.17
As you can see 0.24 > 0.17 ----> P(J)>P(N)
Thus it can be concluded that Juanita gets a strike next game is more likely.
so, choice A
Answer:
24
Step-by-step explanation:
Step 1: We make the assumption that 120 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=120$.
Step 4: In the same vein, $x\%=28.8$.
Step 5: This gives us a pair of simple equations:
$100\%=120(1)$.
$x\%=28.8(2)$.
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{120}{28.8}$
Answer:x+2y-12=0
Step-by-step explanation:
3x+6y=36
-36. -36
3x+6y-36=0
Divide by 3 to get
X+2x-12=0
Answer:
idk sorry ok because I'm dumb
