Answer:
Change 45 min to .75 hrs
Distance = speed * time
Train A's distance = 55(t+.75)
Train B's distance = 70t
The equation
D(t) = 70t + 55(t+.75)
Answer:
B. 75.36 cubic cm
Step-by-step explanation:
We will use the formula V=π times r² times h
so, V= 3.14 times 2² times 6
so, V= 3.14 times 4 times 6
= 3.14 times 24
=75.36 cubic cm
<h2><em>
Please mark me as brainliest</em></h2>
Answer:
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
Step-by-step explanation:
We formulate null and alternate hypotheses are
H0 : u1 < u2 against Ha: u1 ≥ u 2
Where u1 is the group tested after they were awake for 24 hours.
The Significance level alpha is chosen to be ∝ = 0.05
The critical region t ≥ t (0.05, 13) = 1.77
Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13
Here the difference between the sample means is x`1- x`2= 35-24= 11
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/13 [ 120²+360²]
Sp = 105.25
The test statistic is
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 11/ 105.25 √1/5+ 1/10
t= 11/57.65
t= 0.1908
The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level
2 ;) was this helpful? mark me as the best!
