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alina1380 [7]
3 years ago
7

Does anyone live in Alabama

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

yes lots of people live in Alabama there is 4.903 million (2019) but that was in 2019 and people dont know how much there is in 2020 so were still figuring it out but yes there are 4.903 million (2019) people living in  Alabama right now

Step-by-step explanation:

i hope this helps

Crank3 years ago
4 0

Answer: No. Do you?

Step-by-step explanation:

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The Central Limit Theorem says that when sample size n is taken from any population with mean μ and standard deviation σ when n
AVprozaik [17]

Answer:

The correct option is;

B. I only

Step-by-step explanation:

The central limit theorem states that when adequately large random samples are taken from a population that has a mean, μ, and standard deviation, σ, the distributions of the sample means of individual samples taken will be more or less (approximately) normally distributed

The central limit theorem is correct for both normal and skewed populations such that estimates can be made about the population mean based on available sample mean information.

3 0
3 years ago
Rename the mixed number as an improper faction<br><br> a. 3/5<br> b. 12/5<br> c. 2/6<br> d 7/5
Phoenix [80]

Answer:

no

Step-by-step explanation:

7 0
3 years ago
Write the equation of the line that is parallel to the line y= -2x+3 and goes through the point (3, -6).​
svetlana [45]

Answer:

y=-2

Step-by-step explanation:

because it's parallel --> a=-2

therefore we have y=-2x+b

the line goes through the point (3,-6) --> (-2).3+b=-6 --> b=0

3 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
A forest ranger can see for a distance of 12 miles from a firetower.How many square miles can he observe?
mr_godi [17]
I think it is 12x12 = 144

7 0
4 years ago
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