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alina1380 [7]
3 years ago
7

Does anyone live in Alabama

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

yes lots of people live in Alabama there is 4.903 million (2019) but that was in 2019 and people dont know how much there is in 2020 so were still figuring it out but yes there are 4.903 million (2019) people living in  Alabama right now

Step-by-step explanation:

i hope this helps

Crank3 years ago
4 0

Answer: No. Do you?

Step-by-step explanation:

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Please help will give brainlist!​
Yuki888 [10]

Answer:

b=\frac{1}{6}

Step-by-step explanation:

In f(x)=a\cos(b(x-c))+d, b represents a constant related to the period of the function. Here's how it's related:

b=\frac{2\pi}{T}, where T is the period of the function.

We're given T=12\pi, so solving for b:

b=\frac{2\pi}{12\pi}=\boxed{\frac{1}{6}}

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(X-3) (2x-3)= (x-3) (x+1) solve for x
yanalaym [24]

(x  - 3)(2x - 3) = (x - 3)(x + 1)

Do the multiplication both sides,

2 {x}^{2}  - 9x + 9 =  {x}^{2}  - 2x - 3

Arrange the terms to LHS according to their variables,

2 {x}^{2}  -  {x}^{2}  - 9x  +  2x + 9 - 3 = 0 \\  {x}^{2}  - 7x  + 6 = 0


Factorise this polynomial

{x}^{2}  - 6x - 6x + 6 = 0 \\ x(x - 6) - (x - 6) = 0 \\ (x - 1)(x - 6) = 0


So what we notice here is when you're multiplying two numbers you're getting 0 as answer.

So one of them must be 0.

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then x = 1

similarly,

x-6=0

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1. Contaminated water is subjected to a cleaning process. The concentration of the
Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0
3 years ago
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