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kvv77 [185]
3 years ago
9

I NEED HELP FAST PLEASE!!!

Mathematics
1 answer:
hammer [34]3 years ago
3 0

So, we need to figure out how much times the body size of the flea it can jump. First, we need to figure out the size of the flea: <em>2^-4=0.0625</em>

Now that we have the size of the flea, we need to figure out how high it can jump: <em>2^3=8</em>

After we figure out the size of the flea, we need to divide 8 by .0625 because it is inverse operations to multiplication: <em>8/.0625=128</em>

Answer: The flea can jump 128 times higher than it's body size.

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use headlights between sunset and sunrise and at any time when visibility is less than 500 feet to 1000 feet.
daser333 [38]

Use headlights between sunset and sunrise and at any time when visibility is less than 500 feet to 1000 feet: TRUE

<h3>What are headlights?</h3>
  • A headlamp is a lamp connected to the front of a vehicle to illuminate the road ahead.
  • Headlamps are also commonly referred to as headlights, but in the most precise usage, the flashlight is the term for the device itself, and the headlight is the term for the beam of light produced and sold by the device.
  • If you are driving with your high-beam lights on, you must dim them at least 500 feet from any oncoming vehicle to avoid blinding the oncoming driver.
  • If you are within 200-300 feet of the vehicle you are following, you must use low-beam lights.
  • When visibility is less than 500 feet and there is insufficient light/adverse weather, headlights must be turned on for 1/2 hour after sunset to 1/2 hour before sunrise.

Therefore, the statement "use headlights between sunset and sunrise and at any time when visibility is less than 500 feet to 1000 feet" is TRUE.

Know more about headlights here:

brainly.com/question/14836887

#SPJ4

The correct question is given below:
Use headlights between sunset and sunrise and at any time when visibility is less than 500 feet to 1000 feet. TRUE or FALSE

4 0
9 months ago
) a water tank is emptying steadily by 2 liters of water per hour. there were 2 liters of water 6 hours after midnight. let x re
REY [17]
First of all, let's find the water tank total amount
according to the exercice, there were 2 L (L =liters) of water at 6 am (6hours after midnight ).
Consider T as total amount of water
so we have
T=(6×2)+2=14 as we already know it's emptying 2 L per hour

y=14-2x , here is the equation !
6 0
3 years ago
Danny has 48 baseball cards in his collection. He would like to give 3/4 of them to his little brother. How many should he give
MAXImum [283]

It would be: 48 * 3/4 = 36

your answer is 36

4 0
2 years ago
Evaluate the expression when a= 5 and x= -2 -a+6x Thankyou ! !
kirill [66]
The equation would be -5+(-12), so the answer would be -17 :)
5 0
3 years ago
Read 2 more answers
when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by \frac{16}{9} to find x

∵ 0.8x = \frac{16}{9}

- Divide both sides by 0.8

∴ x = \frac{20}{9}

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0
3 years ago
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