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3 years ago

We have removed

1 answer:

8 0

There were $N$ balls but we took $A$ balls out, so there are now $N-A$ balls. We add $B$ balls and now we have $N-A+B$ balls.

The program that computes this (I will use python as language has not been specified is the following):

n, a, b = int(input()), int(input()), int(input())

print(f"There are {n-a+b} balls in the box")

# Hope this helps

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Easy 25 points answer what is it called that you use only 1 and 0 like this 1010010011001100011110001010010101001010101010010101

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Binary. Is the correct answe

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4 years ago

Step into the year 2028. How are people viewing digital video? Or have we moved on to a completely new format?

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In the year 2028 I don't believe our digital video viewing experience would change too much considering most, if not all, the population is already satisfied with how easy, simple, and versatile our current experience is. If everything changes one thing will for sure remain unchanged. That one thing is cinemas, I don't think cinemas will ever change much as they provide a constant source of revenue while providing a place for family and friends to get together to watch a movie before it becomes available to other sources.

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3 years ago

In order for storage devices to be prepared for use, they must be ____________ Group of answer choices pre-prepared loaded initi

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formatted

Explanation:

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3 years ago

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What is a benefit of using client/server network?

ANTONII [103]

The answer is centralization

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3 years ago

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Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

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3 years ago