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JulsSmile [24]
2 years ago
9

A security administrator is reviewing the following information from a file that was found on a compromised host: Which of the f

ollowing types of malware is MOST likely installed on the compromised host?
A. Keylogger
В. Spyware
C. Trojan
D. Backdoor
E. Rootkit
Computers and Technology
1 answer:
Roman55 [17]2 years ago
8 0

Answer:

C. Trojan

Explanation:

In Cybersecurity, vulnerability can be defined as any weakness, flaw or defect found in a software application or network and are exploitable by an attacker or hacker to gain an unauthorized access or privileges to sensitive data in a computer system.

This ultimately implies that, vulnerability in a network avail attackers or any threat agent the opportunity to leverage on the flaws, errors, weaknesses or defects found in order to compromise the security of the network.

In this scenario, a security administrator is reviewing the following information from a file that was found on a compromised host: "cat suspiciousfile.txt."

Some of the ways to prevent vulnerability in a network are;

1. Ensure you use a very strong password with complexity through the use of alphanumerics.

2. You should use a two-way authentication service.

3. You should use encrypting software applications or services.

You might be interested in
What single awk command can be used to display all the login names and their associated numerical user IDs
Luden [163]

Answer:

Used the command syntax; awk -F":" '{ print "username: " $<number location> "\t\tuid:" $<number location> }' <target folder>

Explanation:

Linux operating system is a fast open-source computer platform for programmers and network administrators. Its system is arranged in a hierarchical tree structure with the root represented as "/" (for absolute path).

The passwd is a folder in the Linux OS that holds the login details of all users in the system network. The 'awk' is one of the commands used to get information from a file in a folder. It prints out the result by specifying the location of the values (like the username and user id) as a variable (with prefix '$') and then the target folder.

8 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
2 years ago
What are the correct answers to the following questions?
Lena [83]

Answer:

1. analog sound

2. digital sound

3. pixels

4.  local area network

5.bus

6. slots

Explanation:

4 0
2 years ago
What are some reasons DNS is necessary? Check all that apply. A. It maps local addresses to simple names without editing hosts f
dsp73
Domain Name Servers (DNS) are certainly necessary for easy access of resources across a network. The applicable options of the above are A and B - below are explanations as to why.

A: Computers generally are set to automatically obtain DNS information from the network they are connected to or can be pointed to a specific DNS server. This allows for records of where resources (network attach storage devices, other computers on local network, or even website server details) are located on a “master” kind of list so that the local machine’s host file does not have to be routinely updated to contain new addresses.

B: DNS, as explained partially by the answer to A, maintains a type-able or “human readable” domain name for the actual server’s IP address so we don’t have to memorize or keep a list of IPs for where we want to visit on the web (although, Google’s 8.8.8.8 IP address does make it easy). It shows an association between a name/domain name and an IP address so that we can enter something simple (Google.com) and the computer knows where to go (the server at IP address 8.8.8.8) so it can show you the content you want to see.

C: DNS would only simplify remote access if your were attempting LAN (Local Area Network) remote access of another computer on your network. DNS would not make it easier for remote access of a computer on the internet, as most DNS used in non-commercial settings are created and maintained by third-parties that will not put a specific record for one of your computers in it - not that you would want them to either, since it could lead to an open cyber attack.

D: Network throughput is a fancy phrase for network speed. It could be possible that different DNS servers could process requests faster than others, but it is not likely to increase network speed on the whole as navigating via IP or DNS records will be relatively the same speed.
3 0
2 years ago
Jerome falls sick after eating a burger at a restaurant. After a visit to the doctor, he finds out he has a foodborne illness. O
babunello [35]

Answer: food poisning

Explanation:

either the food wasnt

cooked properly or the food was out of date and went bad

3 0
3 years ago
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