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alex41 [277]
3 years ago
9

A certain first-order reaction is 45.0% complete in 65 s. What are the values of the rate constant and the half-life for this pr

ocess
Chemistry
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:

0.01228s⁻¹ = rate constant

Half-life = 56.4s

Explanation:

The first order reaction follows the equation:

ln[A] = -kt + ln[A]₀

<em>Where [A] is amount of reactant after time t = 45.0%, k is rate constante and [A]₀ initial amount of reactant = 100%</em>

ln[45%] = -k*65s + ln[100%]

-0.7985 = -k*65s

0.01228s⁻¹ = rate constant

Half-life is:

Half-life = ln2 / k

<h3>Half-life = 56.4s</h3>

<em />

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