Answer:
t = 1.983 s
Explanation:
- A → Pdts
- - rA = K (CA)∧α = - δCA/δt
∴ α: order = 2
∴ K: rate constant = 0.670/M.s.....T = 300°C
⇒ - δCA/δt = (0.670/M.s)(CA²)
⇒ - ∫δCA/CA² = (0.670)∫δt
⇒ [ 1/CA - 1/CAo ] = 0.670*t
∴ CA = 0.360 M
∴ CAo = 0.690 M
⇒ [ 1/0.360 - 1/0.690 ] = 0.670*t
⇒ [ 1.3285/M ] = (0.670/M.s)*t
⇒ t = 1.983 s
Answer:
Explanation:
H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)
mole of NaOH = 23.6 * 10 ⁻³L * 0.2M
= 0.00472mole
let x be the no of mole of H3PO4 required of 0.00472mole of NaOH
3 mole of NaOH required ------- 1 mole of H3PO4
0.00472mole of NaOH ----------x
cross multiply
3x = 0.0472
x = 0.00157mole
[H3PO4] = mole of H3PO4 / Vol. of H3PO4
= 0.00157mole / (10*10⁻³l)
= 0.157M
<h3>The concentration of unknown phosphoric acid is 0.157M</h3>
The given reaction is:
H2(g) + CO2(g) → H2O(g) + CO(g)
i.e.
H-H + O=C=O → H-O-H + C≡O
Reaction enthalpy (ΔH) is given as:
ΔH = ∑ΔH(Bonds broken) + ∑ΔH(Bonds formed)
= [1*ΔH(H-H) + 2*ΔH(C=O)] + [2*ΔH(O-H) + 1*ΔH(C≡O)]
=[+436 +2(799)] + [2(-463) +1(-1072)] = 36 kJ/mol
The enthalpy change for the given reaction is 36 kJ/mol
Explanation:
I would say its B
Because Qualitative observation deals with data that can be observed with our senses: sight, smell, touch, taste, and hearing. They do not involve measurements or numbers. For instance, colors, shapes, and textures of objects are all qualitative observations. so its using your 5 senses