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Anni [7]
3 years ago
12

What is the midpoint shown below

Mathematics
1 answer:
vekshin13 years ago
6 0
Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)

In this case, the points would be: (1,2) and (1,-5); therefore:
M=((1+1)/2 , (2-5)/2)=(2/2,-3/2)=(1, -3/2)

<span>Answer: B) (1,-3/2)</span>
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What is the area of a rectangle if the length is (4x + 2) cm and a width of (5x – 3) cm
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Answer:

20x^2−2x−6

Step-by-step explanation:

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4 0
3 years ago
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In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles,
bonufazy [111]

Answer:

Phillipa rode the most in May and rode the least in March.

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

Step-by-step explanation:

Given:

In April, Phillipa rode 13 . 5 + 8 . 7 + 11 . 1 miles on her bicycle. In March, she rode ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 miles, and in May, she rode 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) miles.

To find: the month when she rode the most and the month when she rode the least

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Distance travelled by Phillipa on her cycle in March = ( 13 . 5 + 8 . 7 + 11 . 1 ) ÷ 2 = \frac{132}{2}=66 miles

Distance travelled by Phillipa on her cycle in May = 4 × ( 13 . 5 + 8 . 7 + 11 . 1 ) = 4 × 132 = 528 miles

So, she rode the most in May and rode the least in March

Distance travelled by Phillipa on her cycle in May = 8 × Distance travelled by Phillipa on her cycle in March  

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