Formula for distance between two points:
d = √((x₂-x₁)² + (y₂-y₁)²)
Let point 1 be (-3, 11) and point 2 be (5, 5)
Therefore x₁ = -3, y₁ = 11, x₂ =5, y₂ = 5, and substituting in the formula above.
d = √((x₂-x₁)² + (y₂-y₁)²)
= √((5- -3)² + (5-11)²)
= √((5+3)² + (5-11)²)
= √((8)² + (-6)²) 8² = 8*8 = 64, (-6)² = -6*-6 = 36
= √(64 + 36)
= √(100)
= 10
Distance = 10 units.
Answer:
The equation is y = (3/7)x - 7.
Step-by-step explanation:
Given that the point slope form of an equation is y = mx + b where m represents the gradient and b is the y-intercept. Then, you have to substitute the following values into the equation :
The interest earned by $318 investment is 9/100 x 318= $28.62
Since the second equation gives a value for a, we can substitute it into the other equation to find a value for B.
Let's substitute b-2 into the first equation wherever there is an a.
a - 3b = 4
(b-2) - 3b = 4
b - 2 - 3b = 4
-2 - 2b = 4
-2b = 6
b = -3
Now let's find a by substituting -3 into either of the equations to find the value of a.
a = b - 2
a = -3 - 2
a = -5
So your solution set is (-5, -3)
