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horrorfan [7]
2 years ago
13

Chang made $156 for 13 hours of work at the same rate, how many hours would he have to work to make $108?

Mathematics
1 answer:
sdas [7]2 years ago
8 0

Answer:

  9 hours

Step-by-step explanation:

"At the same rate" means time and wages are proportional.

  time/wages = t/$108 = (13 h)/$156

  t = 108(13 h)/156 . . . . . . . . . . . . . . . units of dollars cancel

  t = 9 h

Chang would have to work 9 hours to make $108.

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Which point is NOT on the line y = 2x + 3?
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What is the value of x? x+15=2x-40
IrinaVladis [17]

Answer:

55 =x

Step-by-step explanation:

x+15=2x-40

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2 years ago
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Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators
Nata [24]

Answer:

The solution is y=-\frac{12}{12x-30x^2+1}.

Step-by-step explanation:

A first order differential equation y'=f(x,y) is called a separable equation if the function f(x,y) can be factored into the product of two functions of x and y:

f(x,y)=p(x)h(y)

where p(x) and h(y) are continuous functions.

We have the following differential equation

y'=(1-5x)y^2, \quad y(0)=-12

In the given case p(x)=1-5x and h(y)=y^2.

We divide the equation by h(y) and move dx to the right side:

\frac{1}{y^2}dy\:=(1-5x)dx

Next, integrate both sides:

\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C

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-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}

Therefore,

y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}

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