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jarptica [38.1K]
3 years ago
14

Fast I will give brainlist The total number of seats in a movie theater is calculated by adding the area of the upper section gi

ven by 8x? and the area of the
lower section given by 6x2. The theater plans to add an addition of front row seats given by 4x for a total of 138 seats. Which
equation could be used to solve for the number of seats in the front row addition?
A
8x2 + 6x2 + 4x = 138
BY
8x2 + 6x2 - 4x = 138
8x2 - 6x2 + 4x = 138
D)
8x2 - 6x2 - 4x = 138
Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

(888)

Step-by-step explanation:

okay u stupi if u ont kno jkjk i ont kno byee

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The change in inventories,a component of aggregate supply, comprises roughly what percentage of the GDP
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0.5percentage

Step-by-step explanation:

The change in inventories,a component of aggregate supply comprises roughly of 0.5percentage of GDP

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I don't know this please help no links Brainliest
Illusion [34]

Answer:

y=x+1

Step-by-step explanation:

Rise over run. The line starts positive one and goes up one and over one.

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3 years ago
What is the formula for the area A of a trapezoid with parallel sides of length B and D, nonparallel sides of length A and C and
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Answer:

(B) \dfrac12H (B+D)

Step-by-step explanation:

\text{Area of a trapezoid }= \dfrac12 ($Sum of the parallel sides) \times $Height\\Parallel Sides = B and D\\Height =H\\Therefore:\\\text{Area of the trapezoid }= \dfrac12 (B+D) H

The correct option is B.

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3 years ago
A rectangle has a perimeter of (20x+12y). If one side of the rectangle is (3x-4y), write the expression for the other side
Nady [450]

Answer:

(7x + 10y)

Step-by-step explanation:

To find this add (3x - 4y) to itself to calculate to lengths of the shorter sides.

(3x - 4y) + (3x - 4y) = 6x - 8y

Subtract this from (20x + 12y)

(20x + 12y) - (6x - 8y) = 14x + 20y     Divide this by two to get the length of one side

14x + 20y / 2 = 7x + 10y

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3 0
3 years ago
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
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