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Eduardwww [97]
3 years ago
14

Write a sequence that has four arithmetic means between 2 and 17.

Mathematics
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

a

0

=

44

 

XXX

a

1

=

?

XXX

a

2

=

?

XXX

a

3

=

?

XXX

a

4

=

92

Step-by-step explanation:

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Is 6-6 and 1-6 equal
uranmaximum [27]

Answer:

no

Step-by-step explanation:

6-6=0

1-6=-5

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3 years ago
Please help?!?!?!?! Thanks if you do
Fynjy0 [20]
The answer:  F = 1.7 ml

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What is the length of XPY in terms of pi?
rosijanka [135]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
What is the solution set for -4 x - 10 ≤ 2?<br> A. x ≤ -3<br> B. x ≥ -3<br> C.x ≤ -3<br> D. x ≥ 2
kramer

Answer:

B. x ≥ -3

Step-by-step explanation:

-4 x - 10 ≤ 2

add ten by both sides

-4x≤12

divide -4 by both sides

x ≤ -3

BUT because you divded  you have to switch the sign so

x ≥ -3

6 0
2 years ago
Read 2 more answers
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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