-Polynomials don't have answers.
This question just wants you to add 2 polynomials.
The pencil work under the first one is incorrect.
Here's what you need to do to find the sum of polynomials:
-- Remove parentheses.
(If there's a plus sign before the whole parentheses, then just erase the parentheses. If there's a minus sign before the whole thing, then change the sign of each term inside, and erase the parentheses.)
-- Add up all the x² terms.
Like this ...
x² + x² = 2x²
or
2x² + 7x² = 9x²
-- Add up all the x³ terms the same way.
-- Add up all the 'x' terms the same way.
-- Add up the plain numbers.
-- Write down all the sums as a new polynomial.
Answer is C. X=-11/3 x=-1. Hope this helps!
Let's work on the left side first. And remember that
the<u> tangent</u> is the same as <u>sin/cos</u>.
sin(a) cos(a) tan(a)
Substitute for the tangent:
[ sin(a) cos(a) ] [ sin(a)/cos(a) ]
Cancel the cos(a) from the top and bottom, and you're left with
[ sin(a) ] . . . . . [ sin(a) ] which is [ <u>sin²(a)</u> ] That's the <u>left side</u>.
Now, work on the right side:
[ 1 - cos(a) ] [ 1 + cos(a) ]
Multiply that all out, using FOIL:
[ 1 + cos(a) - cos(a) - cos²(a) ]
= [ <u>1 - cos²(a)</u> ] That's the <u>right side</u>.
Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.
So, on the <u>right side</u>, you could write [ <u>sin²(a)</u> ] .
Now look back about 9 lines, and compare that to the result we got for the <u>left side</u> .
They look quite similar. In fact, they're identical. And so the identity is proven.
Whew !
<h3>Answer:</h3>
The Slope is 
<h2>Explanation:</h2>
Notice that both the points, 
and 
, are on the line. So we can use those points to calculate the slope. Recall that that slope of the line 
can be calculated by 
if we have the points, 
and 
.
<h3>Calculating for the slope of the line:</h3>
Given:
