Ok since your given two points of (-5,2) and origin which is always (0,0) you can find the slope with this formula of y2-y1/x2-x1 plug them in the formula and you should get 0-2/0-5 which is equal to -2/-5 or 2/5 negative signs cancel out now you found your slope but remember the promblem was asking for perpendicular slope to get this you simply flip or reciprocate the slope and take take the opposite sign in our case the slope is 2/5 but the perpendicular version is -5/2 hope this helps.
X(p-6) = z-8 => x = (z-8)/(p-6) if p≠6
You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1
Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
11*5*7
385 breaks down to 7 and 55. Bring the seven down. Break 55 down to 11 and 5. Then bring those down and you get 11*5*7
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
