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Leya [2.2K]
1 year ago
6

This week, Ty works 6 hours pulling weeds, 4 hours raking leaves, and 9 hours

Mathematics
1 answer:
Artyom0805 [142]1 year ago
8 0

Answer:6(a)+4(b)+9(c)

Step-by-step explanation:

Im pretty sure there was an equation that you did not put.

But the equal used to solve would be 6(a)+4(b)+9(c)

a= money earned pulling weeds

b=money earned raking leaves

c=money earned cutting grass.

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it costs $2 to spin the spinner shown below. if you land on an even number, you win $10. if you land on an odd number, you get $
Svetlanka [38]

Answer:

$1

Step-by-step explanation:

because there is more odd numbers then even

4 0
3 years ago
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A long distance runner ran 4x4x4x4x4x4 miles last year. How many miles is this?
Archy [21]

Answer:

4096

Step-by-step explanation:

4x4x4x4x4x4=4^6

Group them to multiply to make it easier:

4x4=16

4x4=16

4x4=16

16x16x16=4096

honestly just plug it into a calculator

3 0
3 years ago
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30 points: 5 star and best answer and thanks. you can leave answers in. A B C or D ty ty ty.
nalin [4]
1, B 2, C 3, C 4, C 5, a 6, b 7, b 8, C 9, a I think. Hoped this helps.
5 0
3 years ago
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Use Euler’s Formula to find the missing number.<br> Edges: 37<br> Faces: 25<br> Vertices: ?
matrenka [14]

Answer:

Step-by-step explanation:

Comment

The formula that relates edges faces and vertices is  F + V = E + 2

Givens

Edges (E): 37

Faces (F) = 25

Vertices: x

Solution

25 + x = 37 + 2                Subtract 25 from both sides.

25-25 +x= 37 - 25 + 2    Combine

x = 12 + 2

x = 14

Answer: The vertices =<u> 14</u>

7 0
2 years ago
There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17
blondinia [14]

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

4 0
3 years ago
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