PLEASE HELP ME!!!!!!!!! x/30 = 150/100

Find the derivative using power rule f(x)=√5x

Lubov Fominskaja [6]

<h2>Finding the Derivative of a Function</h2><h3>Answer:</h3>

$f'(x) = \frac{\sqrt 5}{2 \sqrt x}\\$

<h3>Step-by-step explanation:</h3>

Given:

$f(x) = \sqrt{5x}$

Note: You can always comment if I have misinterpreted the Given

Please refer to Part a of my Answer from this Question to know more about the needed information: brainly.com/question/24699388

Solving for $\frac{\mathrm{d}}{\mathrm{d}x}(f(x))\\$ :

$\frac{\mathrm{d}}{\mathrm{d}x}(f(x)) = \frac{\mathrm{d}}{\mathrm{d}x}(\sqrt{5x}) \\ f'(x) = \frac{\mathrm{d}}{\mathrm{d}x}(\sqrt 5 \cdot \sqrt x) \\ f'(x) = \sqrt 5 \cdot \frac{\mathrm{d}}{\mathrm{d}x}(\sqrt x) \\ f'(x) = \sqrt 5 \cdot \frac{\mathrm{d}}{\mathrm{d}x}(x^{\frac{1}{2}}) \\ f'(x) = \sqrt 5 \cdot (\frac{1}{2}x^{\frac{1}{2} -1}) \\ f'(x) = \frac{\sqrt 5}{2}(x^{\frac{1}{2} -\frac{2}{2}}) \\ f'(x) = \frac{\sqrt 5}{2}(x^{-\frac{1}{2}}) \\ f'(x) = \frac{\sqrt 5}{2 \sqrt x}$

3 0

3 years ago

At a local fitness center, members pay anan $88 membership fee and $44 for each aerobics class. Nonmembers pay $55 for each

Ksivusya [100]

88 + 44c = 55c
88 = 55c - 44c
88 = 11c
88/11 = c
8 = c <== they will cost the same at 8 classes

3 0

4 years ago

What is the measure of Arc AB.

kow [346]

Answer:

65°

Step-by-step explanation:

plz if I'm right follow me and Mark me as brainliest

3 0

3 years ago

What's the answer to this problem??? twenty divided by a number h is 60

Mashcka [7]

20 dived by 60 equals 0.3

3 0

4 years ago

Question 1

vivado [14]

Answer:

For Lin's answer

Step-by-step explanation:

When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.

Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.

Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.

7 0

3 years ago

Read 2 more answers