Answer:
a
Step-by-step explanation:ddk.s\
welcome
Answer:
B) y=2x+3
Step-by-step explanation:
Hello there.
To answer this question, we need to remember some properties about the vertex of quadratic functions.
Let . Its vertex can be found on the coordinates such that and , in which .
Using the coefficients given by the question, we get that:
Thus, we have:
So the statement is true, because the coordinate of the vertex of the function is equal to
Answer:
x^2 + {a/(a + b) + (a + b)/a}x + 1 = 0
Delta = {a/(a + b) + (a + b)/a}^2 - 4
= {a/(a + b)}^2 + {(a + b)/a}^2 + 2 - 4
= {a/(a + b)}^2 + {(a + b)/a}^2 - 2
= {a/(a + b) - (a + b)/a}^2
If a is not equal to zero and a is not equal to -b => delta is always larger than 0
=> Solution 1 = - [ {a/(a + b) + (a + b)/a} + |{a/(a + b) - (a + b)/a}| ]/2
=> Solution 2 = - [ {a/(a + b) + (a + b)/a} - |{a/(a + b) - (a + b)/a}| ]/2
Hope this helps!
:)