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2 years ago

Round 1.8090 to the nearset hundreths

Mathematics

2 answers:

Allisa [31]2 years ago

8 0

Answer:

1.81

Step-by-step explanation:

nikklg [1K]2 years ago

6 0

Answer:

1.81

Step-by-step explanation:

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Soo I need help... can u help?

Luda [366]

Answer:

I think its (6042 = 1780 + a) but I'm not really sure though but I hope if that helped somehow

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3 years ago

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Part A The ordered pair that represents the intersection of the x-axis and y-axis is called the _ A endpoint B origin C x coordi

lianna [129]

Answer: Part A. B origin Part B. C(0,0)

Step-by-step explanation:

In a coordinate plane, there are two axes

1) x-axis which is the horizontal axis.

2) y-axis which is the vertical axis.

The intersection of both the axes is known as the origin whose coordiantes are (0,0), i.e. at this point value of x =0 and value of y =0.

Part A: The ordered pair that represents the intersection of the x-axis and y-axis is called the <u>origin</u>.

Part B: The coordinate. Part B the coordinates of the origin are <u>(0,0)</u>.

3 0

3 years ago

PLEASE SOLVE THE QESTIONS

jeka57 [31]

Answer:??????????????????

Step-by-step explanation:

3 0

2 years ago

How can you show that two objects are proportional with a table?

vredina [299]

So this is our table:

-----------------
x-values | a b c d e f |
-----------------
y-values | g h i j k l |
-----------------

You can know that the values in the table are proportional if:

$\frac{a}{g}=\frac{b}{h} =\frac{c}{i}=\frac{d}{j}=\frac{e}{k}=\frac{f}{l}$

Hope that helps :)

5 0

3 years ago

When the shaded region below is rotated about the x-axis the resulting solid is a circular cone with radius 2 m and height 3 m.

WARRIOR [948]

Answer:

Therefore, the volume of the cone is V=4π.

Step-by-step explanation:

From task we have a circular cone with radius 2 m and height 3 m. We use the disk method to find the volume of this cone.

We have the formula:

$\boxed{V=\int_0^h\pi \cdot \left(\frac{r}{h}x\right)^2\, dx}$

We know that r=2 and h=3, and we get:

$V=\int_0^3\pi \cdot \left(\frac{2}{3}x\right)^2\, dx\\\\V=\int_0^3 \pi \frac{4}{9}x^2\, dx\\\\V= \frac{4\pi}{9} \int_0^3 x^2\, dx\\\\V= \frac{4\pi}{9} \left[\frac{x^3}{3}\right]_0^3\, dx\\\\V= \frac{4\pi}{9}\cdot 9\\\\V=4\pi$

Therefore, the volume of the cone is V=4π.

7 0

3 years ago