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4 years ago

Min-jun has a swimming pool that needs to be drained. His pool holds

Mathematics

2 answers:

crimeas [40]4 years ago

8 0

You will need to drain 1016.308 gallons an hour

chubhunter [2.5K]4 years ago

8 0

Answer:

The change in the water level per hour for Min-Jun's swimming pool is 1016.31 Gallons per hour.

Step-by-step explanation:

Since we have a total amount of 10,874.5 gallons and 10.7 hours total to drain the full pool we divide the total amount by the total time, assuming that the pool drains at a constant rate. When we divide 10,874.5 by 10.7 we get 10.16.3084... and rounding it to the nearest hundreth or the second decimal place we get 1,016.31 gallons per hour.

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Make x the subject of the formula<br> y = x^2

vazorg [7]

Answer:

$\displaystyle \large{x=\pm \sqrt{y}}$

Step-by-step explanation:

We are given the equation:

$\displaystyle \large{y=x^2}$

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$\displaystyle \large{\sqrt{y}=\sqrt{x^2}}$

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Therefore, the solution is $\displaystyle \large{x=\pm \sqrt{y}}$

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Summary

To make a variable as the subject of equation means to isolate that variable. For an example, if you want to make y as the subject, you’ll have to isolate y-term.

You may also be curious why do you have to add plus-minus on another side when cancelling $\displaystyle \large{\sqrt{x^2}}$ because $\displaystyle \large{\sqrt{x^2}=|x|}$ and $\displaystyle \large{|x|}$ for their positive and their counterparts (opposite/negative) will always give same y-value.

From an example:

$\displaystyle \large{\sqrt{x^2}=4}$ can be rewritten as $\displaystyle \large{|x|=4}$ , cancel absolute sign/square root then write plus-minus which the solution is $\displaystyle \large{x=\pm 4}$ and if you substitute x = 4 or -4, the equation will be true for both values.