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3 years ago

Min-jun has a swimming pool that needs to be drained. His pool holds

Mathematics

2 answers:

crimeas [40]3 years ago

8 0

You will need to drain 1016.308 gallons an hour

chubhunter [2.5K]3 years ago

8 0

Answer:

The change in the water level per hour for Min-Jun's swimming pool is 1016.31 Gallons per hour.

Step-by-step explanation:

Since we have a total amount of 10,874.5 gallons and 10.7 hours total to drain the full pool we divide the total amount by the total time, assuming that the pool drains at a constant rate. When we divide 10,874.5 by 10.7 we get 10.16.3084... and rounding it to the nearest hundreth or the second decimal place we get 1,016.31 gallons per hour.

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Please help, this is for 8th grade math.

expeople1 [14]

Answer:

(2,-2)

Step-by-step explanation:

The first step is to substitute y in the first equation with the right side of the second equation because they both equal to y.

-3x+4 = 4x-10

-3x-4x+4-4 = 4x-4x-10-4

-7x = -14

-7x/-7 = -14/-7

x = 2

Plugin 2 for x for either equation to solve for y, I'll be using the second equation, but either one is fine.

y = 4(2)-10

y = 8-10

y = -2

Plugin x = 2 and y = -2 into (x,y), and you get (2,-2)

6 0

3 years ago

P and q are different two-digit prime numbers with the same digits, but in reversed order. what is the value of the larger of p

serious [3.7K]

The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}

Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original

If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap

8 0

3 years ago

Read 2 more answers

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

4 0

2 years ago

#2 Find the segment length indicated. Assume that lines which appear to be tangent are tangent. *

gregori [183]

The angle of a tangent and a radius is a right angle.

The missing length would be the hypotenuse. Use the Pythagorean theorem to solve.

X = SQRT(12^2 + 16^2)

X = SQRT(144 + 256)

x = SQRT(400)

X = 20

4 0

3 years ago

90 POINTS! HELP PLEASE!!!! I need answers to a-e thank you.

polet [3.4K]

Answer:

(a)Equation representing amount of lights on Monday is 2 x + 3 y = 44

(b)Equation representing amount of lights on Tuesday is 5 x + 3 y = 56

(c) Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

Step-by-step explanation:

Let x = strands of lights on bushes.

Let y = strands of lights on trees.

Bob used 44 strands of light to decorate 2 bushes and 3 trees on Monday.

So, the number of light on 2 bushes = 2x

and the number of light on 3 tress = 3 y

⇒ 2 x + 3 y = 44

Also, On Tuesday, Bob used 56 strands of lights to decorate 5 bushes and 3 trees.

So, the number of light on 5 bushes = 5x

and the number of light on 3 tress = 3 y

⇒ 5 x + 3 y = 56

Now, solving the system of equations:

2 x + 3 y = 44

5 x + 3 y = 56

Subtract equation (2) from (1), we get

2 x + 3 y - (5 x + 3 y) = 44 - 56

or, 2x - 5x = - 12

or, 3x = 12 ⇒ x = 12/3 = 4 or x = 4

Using x = 4 in 2x + 3y = 44

2(4) + 3y = 44

or, 3y = 44- 8 = 36

or y = 36 /3 = 12 or y = 12

So, the value of x = 4, and y = 12

Hence, here Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

8 0

3 years ago