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ipn [44]
3 years ago
6

Is 5(3x +4) equivalent to 15x + 20 ?

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

5(3x+4)

5*3=15

5*4=20

15x+20

mario62 [17]3 years ago
8 0
Yes. You multiply 5 to both sides. 5 x 3x= 15x and 5 x 4 = 20 so yes it would equal 15x+20
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Mrs. Nixon went to the store to buy candy for her
AnnyKZ [126]

Answer:

$2.25

Step-by-step explanation:

First, we (always) highlight key details. In this case, we would highlight that th candy is 90 cents per pound, and the she bought 2.5 pounds. Now, we just multiply 2.5 by .90, and boom! We get $2.25. Mrs. Nixon spent $2.25 (or two dollars and twenty-five cents) on candy bars.

8 0
2 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
marin [14]

Yo sup??

To solve this question we have to apply trigonometric ratios

sin36=XY/WY

WY=XY/sin36

=8.5

Hope this helps.

7 0
3 years ago
What’s the equation for g(x)
taurus [48]

Answer:

g(4)=10

Step-by-step explanation:

4 0
2 years ago
Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0
2 years ago
Order from least to greatest
Orlov [11]
Answer: 
In order from least to greatest: 0.25, 3 ⅜, 3 <span>⅖</span>; 

Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .
___________________________________
Explanation:

0.25 =  ¼ l  (less than "1"); the lowest of the three given values. 

The remaining two values have the same whole number of 3, and a fraction:
   3 <span>⅖ ;</span> and 3 ⅜.

The least common multiples among the denominators of the fraction values is 40.   ⅖ = ?/40 ; 5*? =40? 5* 8 = 40, so 2*8 = 16;
Thus, ⅖ = 16/40, and 3 ⅖ = 3 16/40.  3/8 = ?/40? 8*5 =40; so 3*5 = 15 ; thus ⅜ = 15/40; and
and 3 ⅜ = 3 15/40.
3 15/40 is less than than 3 16/40;  
as such; 3 ⅜ is less than 3 ⅖.

So, in order from least to greatest: 0.25, 3 ⅜, 3 ⅖; 
Or, write as: 0.25 < 3 ⅜ < 3 ⅖ .

7 0
3 years ago
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