The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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Answer:
6÷41 equals 0.14634146341
6÷21 equals 0.28571428571
6÷43 equals 0.13953488372
6÷37 equals 0.16216216216
6÷20 equals 0.3
Step-by-step explanation:
Hope this helps
Answer:
The third one :)
Step-by-step explanation:
The answer will turn out to be 26.87
Answer:
is not possible
Step-by-step explanation:
<u><em>The question in English is</em></u>
we are building a road that links the points a = (12 ,21) and b =(17,23) another point is in c =(3,9) it is possible that a single road allows to join these three points?
we know that
The formula to calculate the slope between two points is equal to

step 1
Find the slope ab
we have
a = (12 ,21) and b =(17,23)
substitute


step 2
Find the slope ac
we have
a = (12 ,21) and c =(3,9)
substitute


simplify

step 3
Compare slopes ab and ac
The slopes are different
That means ----> is not possible that a single road allows to join these three points