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vagabundo [1.1K]
3 years ago
14

Pumps A, B and C operate at their respective constant rates. Pumps A and B, simultaneously, can fill a certain tank in 6/5 hours

. Pump A and C, operating simultaneously, can fill the tank in 3/2 hours; abd pumps B and C, operating simultaneously, can fill the tank in 2 hours. How many hours does it take pumps A, B, and C, operating simultaneously, to fill the tank?(A) 1/3(B) 1/2(C) 2/3(D) 5/6(E) 1
Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0

[NOTE: NO OPTION MATCHES THE ANSWER because values provided are wrong but I have solved the qyestion with the given values for your understanding, If B and C will take 1/2 hours then the answer will be 1 that is Option E]

Answer:

Pumps A and B,

A + B = 5/6

Pumps A and C,

A + C = 3/2

Pumps B and C,

B + C = 2

Now we have to find

A + B + C = ?

For this we will add all of the above equations from both sides.

A+B + A+C +B+C = 5/6 + 3/2 + 2

Taking LCM on R.H.S,

2A + 2B + 2C = (5+9+12)/6

2(A+B+C) = 26/6

2(A+B+C)= 13/3

A+B+C = 13/6

It will take 13/6 hours if A,B and C are pumped simultaneously.

[NOTE: NO OPTION MATCHES THE ANSWER because values provided are wrong but I have solved the qyestion with the given values for your understanding, If B and C will take 1/2 hours then the answer will be 1 that is Option E]

Step-by-step explanation:

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Answer:

<u>5</u>

4x^11*y^6

In words:

5 over 4x to the 11th power times y to the 6 power.

Step-by-step explanation:

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<u>5x^9*y^6</u>

4x^20*y^12

=

<u>5y^6</u>

4x^11*y^12

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<u>5</u>

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8 0
2 years ago
What are the solutions of 12 - x2 = 0?
tester [92]

Answer:

±2 sqrt(3) =x

Step-by-step explanation:

12 - x^2 = 0

Add x^2 to each side

12 - x^2 + x^2 = x^2

12 = x^2

Take the square root of each side

±sqrt(12) = sqrt(x^2)

±sqrt(4*3) = sqrt(x^2)

±sqrt(4) sqrt(3) = x

±2 sqrt(3) =x

3 0
3 years ago
Read 2 more answers
Consider the quadratic function f(x) = x2 – 5x + 6.
rusak2 [61]
A = 1
b = -5
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8 0
3 years ago
Which graph is the graph of this fucntion
OverLord2011 [107]
<h2>Answer:</h2>

Graph C

<h2>Step-by-step explanation:</h2>

This is a piecewise-defined function because it is defined by two equations over a specified domain and this domain is [0,5]. The first function comes from the pattern of the square root function f(x)=\sqrt{x} and the second one is a linear function.

The graph of 3\sqrt{x+1} has been shifted one unit to the left of f(x)=\sqrt{x} and stretched vertically where each y-value is multiplied by 3.

Moreover, we can prove that:

The graph of 3\sqrt{x+1} passes through points (0,3) and (3,6):

y= 3\sqrt{x+1} \\ \\ \\ \bullet \ (0,3): \\ \\ let \ x=0: \\ \\ y= 3\sqrt{0+1} \therefore y=3\sqrt{1} \therefore y=3(1) \therefore y=3 \\ \\ \\ \bullet \ (3,6): \\ \\ let \ x=3: \\ \\ y= 3\sqrt{3+1} \therefore y=3\sqrt{4} \therefore y=3(2) \therefore y=6

It passes through these points.

The graph of 5-x passes through points (5,0) and (3,2):

y=5-x \\ \\ \\ \bullet \ (5,0): \\ \\ let \ x=5: \\ \\ y=5-0 \therefore y=5 \\ \\ \\ \bullet \ (3,2): \\ \\ let \ x=3: \\ \\ y=5-3 \therefore y=2

It passes through these points.

____________________

<h3>Finally, the graph is shown bellow and matches Graph C.</h3>

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tankabanditka [31]
3x1000+2x100+4x10+6x1+7x(1/10)+8x(1/100)
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