In order to get the figure, you have to plot it.
Quadlirateral ABCDwith <span>vertices: A(-4, -3), B(2, -3), C(4, -6), and D(-4, -6) is </span>s A. TRAPEZOID
A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to
. The <em>measures</em> of the internal <u>angles</u> of the <u>triangle</u> given in the question are A =
, B =
, and C =
.
A <u>triangle</u> is an example of a class of <em>figures</em> referred to as <em>plane shapes</em>. It has <u>three</u> straight <u>sides</u> and <u>three</u> internal <u>angles</u> which sum up to
.
Considering the given question, let the <u>sides</u> of the triangle be: a = 6 km, b = 6.5 km, and c = 7 km.
Apply the <em>Cosine rule</em> to have:
=
+
- 2ab Cos C
So that;
=
+
- 2(6 * 6.5) Cos C
49 = 36 + 42.25 - 78Cos C
78 Cos C = 78.25 - 49
= 29.25
Cos C = 
= 0.375
C =
0.375
= 67.9757
C = 
Apply the <em>Sine rule</em> to determine the <u>value</u> of B,
= 
= 
SIn B = 
= 0.861
B =
0.861
= 59.43
B = 
Thus to determine the value of A, we have;
A + B + C = 
A +
+
= 
A =
- 127.4
= 52.6
A = 
Therefore the <u>sizes</u> of the <em>internal angles</em> of the triangle are: A =
, B =
, and C =
.
For more clarifications on applications of the Sine and Cosine rules, visit: brainly.com/question/14660814
#SPJ1
In this question , it is given that , the width of a rectangle is 6 2/3 inches.The length of the rectangle is twice its width.
First we need to convert mixed fraction to improper fraction.

And length is twice of width, so length is

The formula of perimeter is two times the sum of length and width.
