All categories

3 years ago

Law of sines: sin(A)/a=sin(B)/b=sin(C)/c How many distinct

Mathematics

1 answer:

Mariana [72]3 years ago

3 0

Answer:

According to the given question if one of the angle of the triangle is 75 degree and the other two sides are of length 2 and 3 units respectively then option C is correct. Only One triangle can be formed where Angle B will be 40 degree. You can figure it out from the steps mentioned below first of all draw an Arc with the length either 3cm or 2 cm that will be the base of a triangle and then from the ending point again cut an arc then after from the starting point that is the point draw an angle of 75 degree with the help of protactor and extend it to meet the Arc finally you can get the 40 degree.

Hope this helps. Name me brainliest please

You might be interested in

Solve for x. M=5/dx+e

snow_lady [41]

After solving $M=\frac{5}{dx}+e$ we get value of x: $x=\frac{5}{(M-e)d}$

Step-by-step explanation:

We need to solve the equation $M=\frac{5}{dx}+e$ to find value of x

Solving

$M=\frac{5}{dx}+e$

Adding -e on both sides

$M-e=\frac{5}{dx}+e-e$

$M-e=\frac{5}{dx}$

Multiply both sides by dx

$dx(M-e)=5$

Divide both sides by M-e

$dx=\frac{5}{M-e}$

Divide both sides by d

$x=\frac{5}{(M-e)d}$

So, After solving $M=\frac{5}{dx}+e$ we get value of x: $x=\frac{5}{(M-e)d}$

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

8 0

3 years ago

The sides of a rhombus with angle of 60° are 6 inches. Find the area of the rhombus.

ehidna [41]

1. Check the drawing of the rhombus ABCD in the picture attached.

2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.

3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°

ii) are perpendicular to each other, so m(DOC)=90°

4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.

5. By the pythagorean theorem, $DO= \sqrt{ DC^{2}- OC^{2} }= \sqrt{ 6^{2}- 3^{2} }=\sqrt{ 36- 9 }=\sqrt{ 27 }= \sqrt{9*3}=$
$=\sqrt{9}* \sqrt{3} =3\sqrt{3} (in)$

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4* $\frac{DO*OC}{2}=4 \frac{3 \sqrt{3} *3}{2}$ = $=2*9 \sqrt{3}=18 \sqrt{3}$ ( $in^{2}$ )

6 0

3 years ago

17.381 divided by 1.21

daser333 [38]

Answer:

14.36446281 is the answer, you probably have to round

7 0

3 years ago

Please answer it correctly and I'll mark it

kirza4 [7]

Answer:

Step-by-step explanation:

1) a very poor question indeed. It has at least two possible solutions

c = 3x + 2 or c = 3(x + 2)

when x = 2

c = 3(2) + 2 = 8 or c = 3(2 + 2) = 12

when x = 5

c = 3(5) + 2 = 17 or c = 3(5 + 2) = 21

y = x + 2

when x = 2

y = 2 + 2 = 4

when x = 5

y = 5 + 2 = 7

8 0

2 years ago

7+ 10 = 16 + 2 true or false

KATRIN_1 [288]

Answer:

no bc if you simplify it's 17=18 which is not right

5 0

3 years ago

Read 2 more answers