Let's solve your system by substitution.
a=−2;b=−3
Step: Solve a=−2for a:
a=−2
Step: Substitute−2for a in b=−3:
b=−3
b=−3
Answer:
a=−2 and b=−3
Answer:
the second friend
Step-by-step explanation:
Answer:
$80,000
Step-by-step explanation:
240,000/3=80,000
80,000x1=80,000
We will be using the fact that 
, where 
is the probability that the first bulb works and 
is the probability that the second bulb works.
The probability that the first bulb works is 
. However, when we take one out (given that the first bulb works) we now have 19 working bulbs and 4 bad ones. This means that the probability that the second bulb works is 
.
Now, we can find our final probability:
I am not sure if I understand the question that clearly but if what I think is correct is that you need to prove that 2 and 1 are a system of equations for the following equations so this is how you do that:
With the coordinates (2,1) 2 will be x and 1 will be y because when dealing with coordinates (x,y) is how they are set up.
Next you substitute into the equations and solve:
(2) + 3(1) = 5 and 1 = -(2)+3
So now you find if the equations are true
2 + 3 = 5 so (2,1) is a solution for this equation
-2 + 3 = 1 so (2,1) is also a solution for this equation
So in conclusion (2,1) is a solution of the system of equations
Hope this helps :)
