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3 years ago

15

The record high January temperature in Austin Texas is 90 Fahrenheit the record low January temperature is -2 Fahrenheit find th

e difference between the high and low temperatures

1 answer:

Dvinal [7]3 years ago

6 0

The difference is 92

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Help me please. How to prove this ?

podryga [215]

Answer:

First, you want to divide the numerator and denominator by the cosine(x), and afterwards, it looks like this...

$\frac{tan~x+1}{tan~x-1}$

Include 45 as one of the parameters and correlate with <em>tan</em>.

$\frac{tan~x+tan~45}{tan~x-tan~45}$

Next, you want to multiply the numerator and denominator by the conjugate of the denominator, in this case, <em>tan x + tan 45.</em>

Lastly, simplify, and you have the answer as <em>tan(45 + x)</em>

3 0

2 years ago

x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at which point? (1, -1) (-1, 1) (0, 3/2)

gtnhenbr [62]

I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.

4 0

3 years ago

-1(t+8)=-7.1 solve for t

Darina [25.2K]

Answer:

t = -0.9

Step-by-step explanation:

-1(t+8) = -7.1

(t+8) = 7.1

t = -0.9

7 0

3 years ago

Read 2 more answers

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

4 0

3 years ago

How to solve this one

djyliett [7]

Step-by-step explanation:

It's a growth exponential graph.

Domain = All real numbers

Range= y>-5

y-int= -5

x=0 , so 3^0-5=-5

Asymptote: -5

5 0

3 years ago