No, this is not true every time. It depends on the conditions given.
For example-
Suppose we have a Box A with dimensions 10 x 10 x 1 and Box B with dimensions 5 x 5 x 5.
Box B has a surface area = 2(25+25+25) = 150 and a volume of 5*5*5= 125 cubic units
Box A has a larger surface area = 2(100+10+10) = 240 and a smaller volume = 10*10*1 = 100 cubic units
Similarly take an example of sphere.
Lets suppose the radius of the sphere is 2 cm
So, SA is 4πr² = 4*3.14*2*2 = 50.24 cm²
Volume of the sphere is = 4πr³ /3 = 33.50 cm³
Here also the SA is greater.
Answer:
The answer is D) 6 1/4 to win a bet
Unit rates are easy you just take the first number and divide it by your second
15 divided by 5 is = 3
75 divided by 25 is = 3
80 divided by 4 is = 20
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Here it is given that the width is x ft and total length of the fence is 2400 ft .
Let the length be y ft
So we have

Let A represents area, and area is the product of length and width .
So we get

Substituting the value of y, we will get

Second part
The area is maximum at the vertex, and vertex is

And

And that's the required dimensions .