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AysviL [449]
3 years ago
8

Solve: k = -45 ÷ (-15). GIVING BRAINLIST!!!

Mathematics
2 answers:
DerKrebs [107]3 years ago
4 0

Answer: k - 3

Step-by-step explanation:

i just used the rules for division, and removed the parentheses.

k = 45 / 15

once i got to here, i just did simple division. :)

k = 3

Verizon [17]3 years ago
4 0

Answer:

k=3

Step-by-step explanation:

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Help me please!!!!!!!​
user100 [1]

Answer:

C

Step-by-step explanation:

The explanation in option choice C is better than what I can give, but the triangles are similar, meaning they either share angles or side lengths, not congruent, where they have to share both.

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3 years ago
The base of a rectangular prism has an area of 8 square meters. The height of the rectangular prism is 5 meters.
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the point (4,0) lies on a circle with the center at the orgin. what is the area of the circle to the nearsest hundreth?
kvasek [131]

Answer:

50.27 units²

Step-by-step explanation:²

The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius.  Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.

The formula for the area of a circle is A = πr².

Here, with r = 4, the area is A = π(4 units)² = 16π units², or

50.27 units² to the nearest hundredth.

3 0
3 years ago
Trick question<br> whats 50 divided by half plus 10
hoa [83]
50:\frac{1}{2}+10=50\cdot\frac{2}{1}+10=50\cdot2+10=100+10=\boxed{110}
5 0
3 years ago
There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
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