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3 years ago

I need help correct answer will get brainliest.

Mathematics

2 answers:

Arturiano [62]3 years ago

8 0

Answer:

2.75124851367

Step-by-step explanation:

8/8.41=951248513674+1.8=2.75124851367 so its 2.75124851367

Elodia [21]3 years ago

4 0

Answer:

2.85125 is the answer.

Step-by-step explanation:

according to the calculator

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Jalen bought 4 bottles of water, 2 bags of cashews, and a fruit salad. The cost of the fruit salad was $5.

Ede4ka [16]

Answer:2

Step-by-step explanation: 2x2=4 therefore 4 is double 2

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3 years ago

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

olga nikolaevna [1]

$f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i$

${x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4$

The Lagrangian is

$L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)$

with partial derivatives (all set equal to 0)

$L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}$

for $1\le i\le n$ , and

$L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0$

Substituting each $x_i$ into the second sum gives

$\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4$

Then we get two critical points,

$x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}$

$x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}$

At these points we get a value of $f(x_1,\cdots,x_n)=\pm2\sqrt n$ , i.e. a maximum value of $2\sqrt n$ and a minimum value of $-2\sqrt n$ .

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4 years ago

6y+9-4y=-3 Please solve with work

Ronch [10]

1)combine like terms
2) move 9 to the other side by subtracting 9
3) divide by the # that is in front of y - to both sides
answer you should get: -11/2

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4 years ago

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It has been estimated that the price elasticity of demand for attending baseball games is 0.23. Other things held constant, a 10

Akimi4 [234]

Answer:

Correct option: (A) 43.48% fall in the price of a ticket.

Step-by-step explanation:

The price elasticity of demand is defined as the percent change in quantity demanded to the percent change in the price.

$Price\ elasticity\ of\ demand=\frac{\%\ change\ in\ quantity\ demanded}{\%\ change\ in\ price}$

Given:

Price elasticity of demand = 0.23

% change in quantity demanded = 10

Compute the % change in price as follows:

$Price\ elasticity\ of\ demand=\frac{\%\ change\ in\ quantity\ demanded}{\%\ change\ in\ price}\\0.23=\frac{10}{\%\ change\ in\ price}\\{\%\ change\ in\ price}=\frac{10}{0.23}\\=43.4783\\\approx43.48$

Thus, a 10 percent increase in attendance can be explained by a 43.48% fall in the price of a ticket.

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3 years ago

A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. Supp

Trava [24]

Answer:

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

Step-by-step explanation:

As the test is targeted to 18-to-29-year-old adults using social media, we want to know the probability that a randomly selected adult uses social media and belong to the study group.

To achieve this, we have this data:

- 36% of all adults do not use social media

- 75% of all adults are >30 years old.

- The percentage of population that is either 18-29 years old or uses social media is 66.7%

Using the last data we have that

$P(social\,media=yes\, or\,18-29=yes)=P(social\,media=yes)+P(18-29=yes)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=(1-0.36)+(1-0.75)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=0.64+0.25-P(social\,media=yes\, \&\,18-29=yes)\\\\P(social\,media=yes\, \&\,18-29=yes)=0.64+0.25-0.667=0.223$

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

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3 years ago