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3 years ago

7

What is the greatest common factor of x4, x2, and x?

1 answer:

Komok [63]3 years ago

8 0

The GCF of these terms is x

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Mr.Yatabarry’s new carpet covers 128 square feet. It’s twice as long as it is wide. What are the dimensions of the carpet?

Anvisha [2.4K]

Length: 20ft
Width: 10ft

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3 years ago

The perimeter of a rectangular campsite is 64 cm and its area is 207 cm. Find the length and the breadth of the rectangle.

AlladinOne [14]

Perimeter Formula:
$2l + 2b = 64$

Area Formula:
$l \times b = 207$
Set perimeter Formula equal to b:
$2l + 2b = 64 \\ 2(l + b) = 64 \\ l+ b = 32 \\ b = 32 - l$
Plug formula for be we just made above into the area Formula:
$(32 - l) \times l = 207$

Solve for L (you'll have to use quadratic formula) then plug that back into the area Equation and solve for b.

Here's a link to where the problem has been explained before (they go into more detail than me).

https://brainly.ph/question/468631

lmk if you need any more help

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3 years ago

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What challenges might people living in a country or state with high concentration of subprime scores be facing as a result of th

IrinaVladis [17]

Answer:

poverty and hunger

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3 years ago

Write the fraction in lowest terms.<br><br> 13/17

Dmitry [639]

13/17 is at the lowest because they are both prime numbers.

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3 years ago

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Find the perimeter of the triangle defined by the coordinates (7, 1), (-6, 1), and (10, 6). (Round to nearest tenth)

matrenka [14]

Answer:

$35.6\ units$

Step-by-step explanation:

we know that

The perimeter of triangle is equal to the sum of the length of the three sides

Let

$A(7, 1), B(-6, 1), C(10, 6)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(7, 1), B(-6, 1)$

substitute in the formula

$d=\sqrt{(1-1)^{2}+(-6-7)^{2}}$

$d=\sqrt{(0)^{2}+(-13)^{2}}$

$dAB=13\ units$

Find the distance BC

$B(-6, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10+6)^{2}}$

$d=\sqrt{(5)^{2}+(16)^{2}}$

$dBC=16.8\ units$

Find the distance AC

$A(7, 1), C(10, 6)$

substitute in the formula

$d=\sqrt{(6-1)^{2}+(10-7)^{2}}$

$d=\sqrt{(5)^{2}+(3)^{2}}$

$dAC=5.8\ units$

Find the perimeter

$P=dAB+dBC+dAC$

$P=13+16.8+5.8=35.6\ units$

4 0

3 years ago