Answer:
219
Step-by-step explanation:
The figure has the shape of a trapezoid. We find the area of the trapezoid and subtract the area of the rectangular door.
area of trapezoid = (base1 + base2)h/2
area of trapezoid = (20 ft + 12 ft) * 15 ft / 2
area of trapezoid = 32 ft * 15 ft /2
area of trapezoid = 240 ft^2
area of rectangle = length * width
area of rectangle = 7 ft * 3 ft
area of rectangle = 21 ft^2
area to be painted = area of trapezoid - area of rectangle
area to be painted = 240 ft^2 - 21 ft^2
area to be painted = 219 ft^2
Answer: 219 ft^2
Answer:
<u>3.7</u>
Step-by-step explanation:
<u>Given</u>
- sin²θ + cos²θ = 1
- sinθ = 0.27
<u>Solving for cos</u>θ
- cos²θ = 1 - sin²θ
- cos²θ = 1 - (0.27)²
- cos²θ = 0.0729
<u>Finding tan</u>θ
- tanθ = sinθ / cosθ
- tanθ = 0.27 / 0.0729
- tanθ = <u>3.7</u>
<u>Verifying it lies in the range</u>
- θ = tan⁻¹ (3.7)
- θ = 74.88°
- Range is : 0 < θ < π/2 [or 0 < θ < 90°]
- It lies in the range [Verified]
3m 15 m 6 m not dion to scale and find voulume I’d the triangular 4. 90 m3
Answer:
- Elanor's standardized score is 1.19
- Gerald's standardized score is 0.72
- Elanor has higher score
Step-by-step explanation:
To compare Elanor's and Gerald's math scores, we need to standardize them and calculate their z-scores.
z score can be calculated using the formula
z=
where
- M is the mean score of the exam
- s is the standard deviation of the exam
Elanor's standardized score is:
z(e) =
≈ 1.19
Gerald's standardized score is:
z(g)=
≈ 0.72
Since z(e) > z(g), Elanor has higher score
So remember that the distance formula is
.
1.

Distance between (4,-5) and (4,-2) is 3 units.
2.

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.