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3 years ago

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A geometric figure created without using tools is a

1 answer:

Alenkasestr [34]3 years ago

6 0

A geometric figure created without using tools is a sketch.

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the bases of a trapezoid have lengths of 8 feet and 14 feet. Find the length of the midsegment of the trapezoid .

LiRa [457]

Answer:

11 ft

Step-by-step explanation:

The midsegment is 1/2 of the top and bottom segments

1/2(8+14)

1/2(22) = 11

5 0

2 years ago

-x-1=5 can somebody answer this fo me THX :)

Nitella [24]

Answer: -6

Step-by-step explanation:

-x-1=5

-x=5+1

-x=6

divide both sides by -1

x=-6

8 0

2 years ago

Read 2 more answers

Mr. Brooks is buying a television set for $850. The sales tax is 6%. What will be the total amount he will pay for the televisio

Nonamiya [84]

Hi,

850 $ -- 6%*850 $ = 850 $ -- 6*850/100 $ = 850 $ -- 5100/100 $ = 850 $ -- 51 $ = 799 $.

Easy, huh ?

Green eyes.

5 0

3 years ago

Read 2 more answers

What equation represents the line that passes through points (1.-5) and (3 -17)?

zzz [600]

ALL LINES CAN BE REPRESENTED IN THE FORM $f(x) = ax+b$ .

We know that:

$f(1) = -5 \implies a\cdot(1)+b = -5 \implies a+b = -5$

and

$f(3) = -17 \implies a\cdot(3) +b = -17 \implies 3a+b = 17$

Observe that:

$3a+b = 2a+a+b = 2a+(a+b)$

So:

$2a+(a+b) =-17$

But we know that $a+b = -5$ , so:

$2a+(a+b) =-17$

$2a+(-5) = -17$

$2a = -12$

$a = -6$

Since:

$a+b = -5$

$(-6)+b = -5$

$b = 1$

So the line is:

$f(x) = 1-6x$

5 0

3 years ago

A fried chicken franchise finds that the demand equation for its new roast chicken product, "Roasted Rooster," is given by p = 4

LUCKY_DIMON [66]

Answer:

1. $q=(\dfrac{45}{p})^{\frac{2}{3}}$

2. $E_d=-\dfrac{2}{3}$

Step-by-step explanation:

The given demand equation is

$p=\dfrac{45}{q^{1.5}}$

where p is the price (in dollars) per quarter-chicken serving and q is the number of quarter-chicken servings that can be sold per hour at this price.

Part 1 :

We need to Express q as a function of p.

The given equation can be rewritten as

$q^{1.5}=\dfrac{45}{p}$

Using the properties of exponent, we get

$q=(\dfrac{45}{p})^{\frac{1}{1.5}}$ $[\because x^n=a\Rightarrow x=a^{\frac{1}{n}}]$

$q=(\dfrac{45}{p})^{\frac{2}{3}}$

Therefore, the required equation is $q=(\dfrac{45}{p})^{\frac{2}{3}}$ .

Part 2 :

$q=(45)^{\frac{2}{3}}p^{-\frac{2}{3}}$

Differentiate q with respect to p.

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{2}{3}-1}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(p^{-\frac{5}{3}})$

$\dfrac{dq}{dp}=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})$

Formula for price elasticity of demand is

$E_d=\dfrac{dq}{dp}\times \dfrac{p}{q}$

$E_d=(45)^{\frac{2}{3}}(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{(45)^{\frac{2}{3}}p^{-\frac{2}{3}}}$

Cancel out common factors.

$E_d=(-\dfrac{2}{3})(\dfrac{1}{p^{\frac{5}{3}}})\times \dfrac{p}{p^{-\frac{2}{3}}}$

Using the properties of exponents we get

$E_d=-\dfrac{2}{3}(p^{-\frac{5}{3}+1-(-\frac{2}{3})})$

$E_d=-\dfrac{2}{3}(p^{0})$

$E_d=-\dfrac{2}{3}$

Therefore, the price elasticity of demand is -2/3.

3 0

2 years ago