The problem says that the expression (3x + 5)(5x − 1) <span>represents the area of the floor of the building in square meters. Therefore, to solve this problem you have to follow the proccedure shown below.
1. First, to simplify the expression (3x + 5)(5x − 1) you must apply the distributive property. Then, you obtain:
15x</span>²-3x+25x-5
2. Then, you have:
15x²+22x-5
3. As you can see, the correct answer is the last option: 15x²+22x-5
Answer:
11.25 km h^-2
Step-by-step explanation:
Acceleration = increase in velocity / time
= 90 - 0 / 8
= 11.25 km h^-2.
Last one 1/4x
because the opposite of 1/4 is 4/1
I’m pretty sure the answer is C
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
