Company A has a sales position with a yearly salary of $42,000. Company B has a similar sales position with a slary of $39,000 plus 1% conmission on yearly sales.
Let x be the amount of yearly sales
Company A has a sales position with a yearly salary of $42,000.
yearly salary = 42,000
Company B has a similar sales position with a salary of $39,000 plus 1% commission on yearly sales.
1% is 0.01
yearly salary = 39,000+ 0.01x
yearly sales is the salary at company A greater than the salary and conmission at company B
A > B
42000 > 39000+ 0.01x
We solve the inequality
39000+ 0.01x < 42000
Subtract 39000 on both sides
0.01x < 3000
divide by 0.01
x> 300,000
For yearly sales > $300,000, the salary at company A greater than the salary and commission at company B
×by 2 then find 10%and then times the 10% by 2 then add it on
The mistake is in step 3:
I: −2m =−12 − 2n
II: 2m = 8 + 8n
the student set both right sides of the equations equal (−12 − 2n = 8 + 8n), but the left sides aren't equal: first equation has -2m, second has +2m so the signs of one of the equations must be inverted first
Answer:
5
Step-by-step explanation:
8*5=40 and then 20 short answer that are 3 each. that makes up the rest of the 60 points
