Preciso de ajuda urgente, é para amanhã cedo!!

Characteristic of first generation computer<br>

ella [17]

Characteristics

based on vaccum tubes

they were large,slow,low capacity

Magnetic drums for primary memory

used mll

input punched cards and output printsout

expensive

get heated faster

eg. ENIAC,UNIVAC

6 0

3 years ago

Why hasn't 3D printing been more publicly used?

marshall27 [118]

Answer:

Probably because it's really expensive and not well known.

Explanation:

Some metals and plastic are not able to be altered for 3D printing, which makes this harder for some people to get hold of. Most of the materials are also not able to be recycled, which makes it harder.

3 0

3 years ago

The questions are in the pictures, i basically have to create a web page, drop the html code and files below thank you.

matrenka [14]

This contains pretty much what you need:

<!DOCTYPE html>

<html>

<head>

<title>The Page Title</title>

</head>

<body>

<h1>First paragraph</h1>

<p>This is a paragraph of text.</p>

<h2>Second level paragraph</h2>

<p>

Here is an unordered list of options:

<ul>

<li>First</li>

<li>Second</li>

<li>Third</li>

</ul>

Here is another unordered list of options:

<ul>

<li>First</li>

<li>Second</li>

<li>Third</li>

</ul>

Here is an ordered list of options:

<ol>

<li>First</li>

<li>Second</li>

<li>Third</li>

</ol>

</p>

<h4>Third level</h4>

</body>

</html>

3 0

3 years ago

Implement function easyCrypto() that takes as input a string and prints its encryption

jasenka [17]

Answer:

The program written in python is as follows;

import string

def easyCrypto(inputstring):

for i in range(len(inputstring)):

try:

ind = string.ascii_lowercase.index(inputstring[i])

pos = ind+1

if pos%2 == 0:

print(string.ascii_lowercase[ind-1],end="")

else:

print(string.ascii_lowercase[ind+1],end="")

except:

ind = string.ascii_uppercase.index(inputstring[i])

pos = ind+1

if pos%2 == 0:

print(string.ascii_uppercase[ind-1],end="")

else:

print(string.ascii_uppercase[ind+1],end="")

anystring = input("Enter a string: ")

easyCrypto(anystring)

Explanation:

The first line imports the string module into the program

import string

The functipn easyCrypto() starts here

def easyCrypto(inputstring):

This line iterates through each character in the input string

for i in range(len(inputstring)):

The try except handles the error in the program

try:

This line gets the index of the current character (lower case)

ind = string.ascii_lowercase.index(inputstring[i])

This line adds 1 to the index

pos = ind+1

This line checks if the character is at even position

if pos%2 == 0:

If yes, it returns the alphabet before it

print(string.ascii_lowercase[ind-1],end="")

else:

It returns the alphabet after it, if otherwise

print(string.ascii_lowercase[ind+1],end="")

The except block does the same thing as the try block, but it handles uppercase letters

<em> except: </em>

<em> ind = string.ascii_uppercase.index(inputstring[i]) </em>

<em> print(string.ascii_uppercase[ind-1],end="") </em>

<em> print(string.ascii_uppercase[ind+1],end="") </em>

<em />

The main starts here

This line prompts user for input

anystring = input("Enter a string: ")

This line calls the easyCrypto() function

easyCrypto(anystring)

4 0

3 years ago

In Java please,

Bogdan [553]

Answer:

import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter meal total: $");
double meal = input.nextDouble();
double finalAmount = meal + meal *0.09;
if(finalAmount * 0.15 > 8){
finalAmount = finalAmount + 8;
}else{
finalAmount = finalAmount + finalAmount * 0.15;
}
System.out.println("Final amount: $" + finalAmount);
}
}

Explanation:

Firstly, create a Scanner object and print user to input total meal (Line 5-7). Next, add the 9% tax to the meal total (Line 8). Use an if statement to check if the finalAmount multiplied by the 15% of tips is bigger than 8 (Line 10), if so, only add 8 to the final amount (Line 11). If not, add 15% tips to final amount (Line 12). At last, print out the final amount (Line 15).

8 0

3 years ago