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Goryan [66]
3 years ago
10

Preciso de ajuda urgente, é para amanhã cedo!!

Computers and Technology
1 answer:
Papessa [141]3 years ago
5 0


Bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
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2 negative impact of excessive use of computer even in solving mathematical problem.
zlopas [31]

Answer:

Computers are now a days the very important part of each department as well as homes. All people are somehow using computers for their respective needs. As technology always has the negative impacts along with the positive ones so, computer do have some crucial points when taking about students specially.

Following are listed some acts that add to the negativity of computer's usage.

  • Excess use of computers by students while solving mathematical problems lead them to rely totally on the computer. Students don't tend to calculate by their own instead they use computerized calculators for their ease and hence they start lacking even in basic calculations in normal routine also.
  • Computers may impact students routine in such a way that they don't concentrate on their studies while having extreme interest in video games and their favorite seasons and other activities.
  • Using computers more than a certain limit effects eyesight badly. This is the reason today most of the teenagers use spectacles in normal routine.

<h3>I hope it will help you! </h3>
4 0
3 years ago
What is the significance of the Abstract section of a research paper? A. It contains important information such as the author, c
Bond [772]

Answer: A

Explanation:

7 0
2 years ago
EIPP:________.
nikdorinn [45]

Answer:

D. All of these choices are correct

Explanation:

Electronic invoice presentment and payment, otherwise known as EIPP are business-to-business systems that combine e-invoicing and e-payment processes for the purpose of sending invoices to customers via Web portal or via a secure network by the use of a third party service provider. They are also used for receiving payer-initiated, third-party-processed, and ACH-network-settled wire transfers.

4 0
3 years ago
Read 2 more answers
Lenny copied and pasted content from a commercial website into his research paper without citing his source, passing the work of
Sedbober [7]
Lenny might be either suspended
Or might be failed in that particular course
6 0
7 months ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
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