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Vlad1618 [11]
3 years ago
9

Before using large downloaded files that are in a compressed format, it is necessary to_____ them. A) Copy B) Extract C) Open D)

Zip
Computers and Technology
1 answer:
Aleks04 [339]3 years ago
8 0

The answer is zip. God bless

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clinical outcomes and survival differences between primary, secondary and concomitants carcinoma in situ of urinary bladder trea
8_murik_8 [283]

The summary of the research - clinical outcomes and survival differences between primary, secondary and concomitants carcinoma in situ of urinary bladder treated with BCG Immunotherapy is given below.

<h3>What is the summary of the above research?</h3>

Urinary bladder carcinoma in situ (CIS) is a flat, high-grade, and aggressive form of urothelial cancer with a high likelihood of development to muscle-invasive illness and metastatic dissemination.

The study's goal was to compare the clinical histories and survival rates of primary, secondary, and concurrent CIS of the bladder.

Learn more about Immunotherapy at brainly.com/question/14493516

#SPJ1

6 0
1 year ago
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Write a program in c or c++ to perform different arithmeticoperation using switch statement .the program will take two inputinte
baherus [9]

Answer:

C code :

#include<stdio.h>

int main()

{

int j;

float k,l, x;  //taking float to give the real results.

printf("Enter your two operands: ");  //entering the numbers on which      //the operation to be performed.

scanf("%f %f", &k, &l);

 

printf("\n Now enter the operation you want to do: ");

printf("1 for Addition, 2 for Subtraction, 3 for Multiplication, 4 for Division ");

scanf("%d", &j);  //j takes the input for opearation.

 

switch(j)  

{

 case 1:  

  x=k+l;

  printf("%.2f+%.2f=%.2f",k,l,x);   //we write %.2f to get the result //upto 2 decimal point.

  break;

   

 case 2:

  x=k-l;

  printf("%.2f-%.2f=%.2f",k,l,x);

  break;

 case 3:

  x=k*l;

  printf("%.2f*%.2f=%.2f",k,l,x);

  break;

 case 4:

  if(l!=0) //division is not possible if the denominator is 0.

  {

   x=k/l;

   printf("%.2f/%.2f=%.2f",k,l,x);

  }

  else  

   printf("Division result is undefined");

               default:

   printf("\n invalid operation");

}

}

Output is in image.

Explanation:

At first we take two numbers.

Then we take integers from 1 to 4 for Addition, subtraction, multiplication, division respectively.

Then accordingly the case is followed and the operation is performed.

6 0
4 years ago
9.11: Array Expander
vodka [1.7K]

The Array Expander is an illustration of arrays and functions.

  • Arrays are variables that stores multiple values
  • Functions are named statements that are executed when called

<h3>The Array Expander program </h3>

The Array Expander program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This declares the Array Expander function

int* ArrayExpander(int *oldArr, int size){

   //This declares the new array

   int *newArr = new int[size * 2];

//This iteration sets values into the new array

   for (int i = 0; i < size * 2; i++) {

       if(i < size){

           *(newArr+i) = *(oldArr+i);

       }

       else{

           *(newArr+i) = 0;

       }

   }

//This returns a pointer to the new array

   return newArr;

}

//The main method begins here

int main(){

//This declares the length of the array, N

   int N;    

//This gets input for N

   cin>>N;

   int initArr[N];

//If N is between 1 and 50

   if(N > 0 && N <=50){

//This iteration gets values for the array

       for(int i = 0; i<N; i++){

           cin>>initArr[i];

       }

//This calls the Array Expander function

   int *ptr = ArrayExpander(initArr, N);

//This iteration prints the elements of the new array

   for (int i = 0; i < N*2; i++) {

       cout << ptr[i] << " ";

   }

   }

  return 0;

}

Read more abou C++ programs at:

brainly.com/question/27246607

3 0
2 years ago
Which file extension indicates a text document? .ppt .tst .pdf .txt
Ber [7]

Answer:

The answer is .txt

Explanation:

6 0
2 years ago
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Repetition learning rates are the same for everyone, so there is no need to find an activation and break pattern that works
Leviafan [203]

Answer:

true

Explanation:

4 0
3 years ago
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