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dangina [55]
3 years ago
5

Another khan academy pls

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

88, 90, 92

Step-by-step explanation:

I hop this is right can you pls answer this question khan academy.

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6),A(2,−6),A, left parenthesis, 2, comma, minus, 6, right parenthesis, comma B(5, -6)B(5,−6)B, left parenthesis, 5, comma, minus, 6, right parenthesis, C(5, -2)C(5,−2)C, left parenthesis, 5, comma, minus, 2, right parenthesis, and D(2, -2)D(2,−2)D, left parenthesis, 2, comma, minus, 2, right parenthesis.

What is the perimeter of rectangle ABCDABCDA, B, C, D?

units

Thank you

romanna [79]3 years ago
4 0

Answer:

89

Step-by-step explanation:

3 consecutive numbers can be:

x-1, x, x+1 ; for example: 1, 2, 3 (1 is 1 less than 2, and 3 is 1 more than 2)

The sum is all of them added, so

x-1+x+x+1=270; 3x=270; x=90

90 is the middle number though, so the first number is 89

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Let v1=(3,5) and v2=(-4,7) Compute the unit vectors in the direction of |v1| and |v2|?
AleksandrR [38]
By definition, the unit vector of v = (a,b) is
\hat{v} =  \frac{\vec{v}}{|v|}

Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
 (3,5)/√[3² + 5²]
= (3,5)/√34

The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65

Answer:
The unit vector of v₁ in the direction of |v₁} is ( \frac{3}{\sqrt{34}} ,  \frac{5}{\sqrt{34}} )
The unit vector of v₂ in the directin of |v₂| is
( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )

6 0
3 years ago
What is 29+d=54;24,25,26
Yuliya22 [10]

d=54-29

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4 0
3 years ago
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Answer:

1/10

Step-by-step explanation:

Since 5 people share 1/4 gallon, this can be converted into 1/4 times 1/5. This gives 1/20 for everbody. Sheila gives hers to Maria, which means Maria now has 1/20 plus 1/20, which is 2/20, which can be simplified to 1/10.

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OverLord2011 [107]

Answer:

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Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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