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2 years ago

Another khan academy pls

Mathematics

2 answers:

yaroslaw [1]2 years ago

7 0

Answer:

88, 90, 92

Step-by-step explanation:

I hop this is right can you pls answer this question khan academy.

Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6),A(2,−6),A, left parenthesis, 2, comma, minus, 6, right parenthesis, comma B(5, -6)B(5,−6)B, left parenthesis, 5, comma, minus, 6, right parenthesis, C(5, -2)C(5,−2)C, left parenthesis, 5, comma, minus, 2, right parenthesis, and D(2, -2)D(2,−2)D, left parenthesis, 2, comma, minus, 2, right parenthesis.

What is the perimeter of rectangle ABCDABCDA, B, C, D?

units

Thank you

romanna [79]2 years ago

4 0

Answer:

Step-by-step explanation:

3 consecutive numbers can be:

$x-1, x, x+1$ ; for example: 1, 2, 3 (1 is 1 less than 2, and 3 is 1 more than 2)

The sum is all of them added, so

$x-1+x+x+1=270; 3x=270; x=90$

90 is the middle number though, so the first number is 89

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2 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

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$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

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ch4aika [34]

Answer:

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