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Yuki888 [10]
3 years ago
13

HELP I SOO BAD AT THIS HEEELLLLLPPPP!!!

Mathematics
2 answers:
taurus [48]3 years ago
3 0
9 and 7 are the numerators. The greatest common factor between 3 and 7 is 21. Whatever u multiply the bottom by u have to multiply the top by as well
mr_godi [17]3 years ago
3 0

Answer:

9 and 7

Step-by-step explanation:

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To convert a capacity of 8.7 gallons to quarts, which ratio could you multiply by? remember that 1 gallon = 4 quarts.
Papessa [141]
Using the factor label method, you would set up your ratio like so:8.7 gall *  \frac{4 qts}{1 gall}
3 0
3 years ago
A paint store mixed 4 3/4 cans of paint and 7 2/3 cans of white paint did this mixture make?
stira [4]

Answer:

12 5/12 cans of white make

Step-by-step explanation:

6 0
3 years ago
Write the equation in standard form.<br><br> 3x−9=7y
Ket [755]
In standard form the answer will be if you go by (Ax+by=c )then I must say it's 3x-7y=9
6 0
3 years ago
Solve the equation using the quadratic formula.<br> y2-8y + 17 = 0<br> The solution set is
Slav-nsk [51]

Step-by-step explanation:

Formula is:

x=(-b±  √b^2-4ac)/2a

a= 1

b= -8

c= 17

x= (-(-8)±√64-4(1)(17))/2

x= (8±√-4)/2

now

x1= (8+√-4)/2

x2=(8-√-4)/2

7 0
3 years ago
Based on a Comcast​ survey, there is a 0.8 probability that a randomly selected adult will watch​ prime-time TV​ live, instead o
klio [65]

Answer: Our required probability is 0.004672.

Step-by-step explanation:

Since we have given that

Number of adults = 7

Probability of getting adult will watch prime time TV live = 0.8

We need to find the probability that fewer than 3 of the selected adults watch prime time live.

We will use "Binomial Distribution":

here, n = 7

p = 0.8

So, P(X<3)=P(X=0)+P(X=1)+P(X=2)

So, it becomes,

P(X=0)=(1-0.8)^7=0.2^7=0.0000128

P(X=1)=^7C_1(0.8)(0.2)^6=0.0003584\\\\P(X=2)=^7C_2(0.8)^2(0.2)^5=0.0043

So, probability that fewer than 3 of the selected adult watch prime time live is given by

0.0000128+0.0003584+0.0043=0.004672

Hence, our required probability is 0.004672.

6 0
3 years ago
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