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Karo-lina-s [1.5K]
3 years ago
13

What is the sum of -4 1/2 + 3 1/4

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer:

-1

St ifhguerhgihgr

-1

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The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches What is the height of the tr
ExtremeBDS [4]
The height of the triangular base of the pyramid is calculated through the equation,
                                        h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of  x is 30°. Substituting,
                                        h = (cos 30°)(18 in)
                                        h = 15.59 in
Thus, the height of the base is approximately 15.59 inches. 
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Julian sees a common denominator for 3 x 4 + 2
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the denominator would be 12
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Allison measured a line to be 5.4 inches long. If the actual length of the line is 5.5 inches, then what was the percent error o
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Answer:

1.85%

Step-by-step explanation:

→ Find the difference between the actual and predicted

5.5 - 5.4 = 0.1

→ Divide answer by 5.4

0.1 ÷ 5.4 = 0.01851851851

→ Multiply answer by 100

0.01851851851 × 100 = 1.85%

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Its proportion <br><br> please help ASAP <br><br> im offering 90 points
shtirl [24]
<h3>Answer 1a :- </h3>

Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;

→ In 17hrs the boat travels 452km

→ In 1hr the boat will travel 452km/17

→ In 9hrs the boat will travel 452/17km * 9 = 239.29km

\rule{200}4

<h3>Answer 1b:-</h3>

→ A car can travel 156km on 13L gasoline .

→ It will travel 1km on 13/156L of gasoline .

→ It will travel 480km on 13/156*480L = 40L of gasoline .

\rule{200}4

<h3>Answer 2a :-</h3>

→ A boat can go 180 miles on 60L gasoline.

→ It will go 1mile in 60/180L of gasoline.

→ It will go 306 miles in 60/180*306L = 102L of gasoline .

\rule{200}4

<h3>Answer 2b :-</h3>

→ On 51L of gasoline a car can go 408km

→ On 1L of gasoline car will go 408/51 km

→ On 11L of gasoline it will go 408/51*11L = 88km

\rule{200}4

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