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schepotkina [342]
2 years ago
13

A payday loan store charges $45 for a one-month loan of $540. What annual interest rate is this equivalent to?

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
5 0

Answer:

12

Step-by-step explanation:

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Find the HCF of 126 and 420
melamori03 [73]

Answer:

42

Step-by-step explanation:

Find the prime factorization of 126

126 = 2 × 3 × 3 × 7

Find the prime factorization of 420

420 = 2 × 2 × 3 × 5 × 7

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 3 × 7

GCF = 42

3 0
2 years ago
There is an average of 3.5 x 10^−2 kilograms of dissolved salt in each liter of seawater. The Pacific Ocean contains approximate
IgorC [24]
This is the answer check it out

3 0
3 years ago
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What is the volume of a rectangular prism with a height of 6 m, a length of 4 m, and a width of 2 m?
Debora [2.8K]

Answer:

48m

Step-by-step explanation:

Formula: lwh

4*2*6=48m

6 0
2 years ago
What does 6/2(1+2)= <br> need help
Zina [86]

▪ Answer:

9

▪ Step-by-step explanation:

Hi there !

6/2(1 + 2) =

= 3/1 × 3

= 3×3/1

= 9

Good luck !

7 0
3 years ago
Read 2 more answers
The circumference of the circle is increasing at a rate of 0.5 meters per minute. What's the rate of change of the area of the c
morpeh [17]

Answer:

The rate of change of the area of the circle when the radius is 4 meters = 2 meters²/minute ⇒ answer 4

Step-by-step explanation:

* Lets revise the chain rule in the derivative

- If dy/da = m and dx/da = n, and you want to find dy/dx

∴ dy/dx = dy/da ÷ dx/da = m ÷ n = m/n

* In our problem we have

- The rate of increasing of the circumference dC/dt = 0.5 meters/minute

- We need the find the rate of change of the area of the circle

 when the radius is 4 meters

- The common element between the circumference and the area

 of the circle is the radius of the circle

* We must to find dC/dr and dA/dr and use the chain rule to

 find dA/dr

- Find the rate of change of the radius dr/dt

∵ C = 2πr

- Find the derivative of C with respect to r

∴ dC/dr = 2π ⇒ (1)

∵ dC/dt = 0.5 meters/minute ⇒ (2)

- Divide (1) by (2) to get dr/dt by using chain rule

∵ dC/dt ÷ dC/dr = 0.5 ÷ 2π

∴ dC/dt × dr/dC = 0.5 × 1/2π ⇒ cancel dC together and change

   0.5 to 1/2

∴ dr/dt = 1/2 × 1/2π = 1/4π ⇒ (3)

- Find the rate of change of the area dA/dt

∵ A = πr²

- Find the derivative of A with respect to r

∴ dA/dr = 2πr

∵ r = 4

∴ dA/dr = 2π(4) = 8π ⇒ (4)

- Multiply (4) by (3) to get dA/dt by using chain rule

∵ dA/dr × dr/dt = 8π × 1/4π ⇒ divide 8 by 4 and cancel π

∴ dA/dt = 2 meters²/minute

* The rate of change of the area of the circle when the radius is

  4 meters = 2 meters²/minute

3 0
3 years ago
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